제출 #203574

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
203574		Kevin_Zhang_TW	철인 이종 경기 (APIO18_duathlon)	C++17	100 / 100	159 ms	55928 KiB

count_triplets

#include<bits/stdc++.h>
#define pb emplace_back
using namespace std;
using ll = long long;
const int maxn = 300010;
int n, m;
vector<int> edge[maxn];
int low[maxn], st[maxn], stl, dep[maxn];
int cnt_b;
ll gsz;
vector<int> c[maxn];
bool is_ap[maxn];
ll res;
int h;
vector<int> tree_edge[maxn];
int sz[maxn];
void dfs2(int now, int last = 0){
	sz[now] = c[now].size() + (now <= n);
	for (int u : tree_edge[now]) if(u != last) {
		dfs2(u, now);
		sz[now] += sz[u] - 1;
	}
	ll cur = c[now].size();
	if (now > n){
		auto add = [&](ll sz){
			return sz * cur * (gsz - sz-1) + (cur-1) * (cur-2) * sz;
			return (sz) * (gsz-sz-1) * (cur) * 2;
		};
		for (int u : tree_edge[now]) if(u != last) 
			res += add(sz[u]-1);
		if (last)
			res += add(gsz-sz[now]);
		res += cur * (cur-1) * (cur-2);
	}
	else {
		//return;
		for (int u : tree_edge[now]) if(u != last)
			res -= (sz[u]-1) * (gsz-sz[u]);
		if (last)
			res -= (gsz-sz[now]) * (sz[now]-1);
	}
}
void cal(){
	for (int i = h;i < cnt_b;++i){
		for (int u : c[i]) if (is_ap[u]) {
			tree_edge[u].pb(i);
			tree_edge[i].pb(u);
		}
	}
	dfs2(h);
	gsz = 0, h = cnt_b;
}
void dfs(int now, int last = 0){
	static int d;
	++gsz;
	low[now] = dep[now] = ++d;
	st[stl++] = now;
	int cnt_c = 0;
	for (int u : edge[now]) if (u != last) {
		if (!low[u]){
			dfs(u, now);
			++cnt_c;
			low[now] = min(low[now], low[u]);
			if (low[u] >= dep[now]){
				do {
					c[cnt_b].pb( st[--stl] );
				} while (st[stl] != u);
				c[cnt_b++].pb(now);
				is_ap[now] = true;
			}
		}
		else 
			low[now] = min(low[now], dep[u]);
	}
	if (!last && cnt_c < 2)
		is_ap[now] = false;
	--d;
	if (last == 0)
		cal();
}
signed main(){
	ios_base::sync_with_stdio(0), cin.tie(0);
	cin >> n >> m;
	for ( int a, b, i = 0 ; i < m ; ++i) {
		cin >> a >> b;
		edge[a].pb(b);
		edge[b].pb(a);
	}
	h = cnt_b = n+1;
	for (int i = 1;i <= n;++i) if (!low[i])
		dfs(i);
	cout << res << '\n';
}

• Subtask 1: 5 / 5
• Subtask 2: 11 / 11
• Subtask 3: 8 / 8
• Subtask 4: 10 / 10
• Subtask 5: 13 / 13
• Subtask 6: 15 / 15
• Subtask 7: 20 / 20
• Subtask 8: 8 / 8
• Subtask 9: 10 / 10