Submission #203333

#TimeUsernameProblemLanguageResultExecution timeMemory
203333staniewzkiCollecting Stamps 3 (JOI20_ho_t3)C++17
100 / 100
647 ms448928 KiB
#include<bits/stdc++.h> using namespace std; ostream& operator<<(ostream &out, string str) { for(char c : str) out << c; return out; } template<class L, class R> ostream& operator<<(ostream &out, pair<L, R> p) { return out << "(" << p.first << ", " << p.second << ")"; } template<class T> auto operator<<(ostream &out, T a) -> decltype(a.begin(), out) { out << "{"; for(auto it = a.begin(); it != a.end(); it = next(it)) out << (it != a.begin() ? ", " : "") << *it; return out << "}"; } void dump() { cerr << "\n"; } template<class T, class... Ts> void dump(T a, Ts... x) { cerr << a << ", "; dump(x...); } #ifdef DEBUG # define debug(...) cerr << "[" #__VA_ARGS__ "]: ", dump(__VA_ARGS__) #else # define debug(...) false #endif #define REP(i, n) for(int i = 0; i < n; i++) #define FOR(i, a, b) for(int i = a; i <= b; i++) #define ST first #define ND second template<class T> int size(T && a) { return a.size(); } using LL = long long; using PII = pair<LL, LL>; template<class T> auto create(T x) { return x; } int create(int n) { return n; } template<class... Ts> auto create(int n, Ts... x) { return vector(n, create(x...)); } int main() { ios::sync_with_stdio(0); cin.tie(0); int n, len; cin >> n >> len; vector<int> x(n), t(n); REP(i, n) cin >> x[i]; REP(i, n) cin >> t[i]; auto dp = create(n + 1, n + 1, n + 1, 2, LL(1e9 + 1)); vector<int> d(n + 2); FOR(i, 1, n) d[i] = x[i - 1]; d[n + 1] = len; auto left = [&](int a, int b) { return d[b] - d[a]; }; auto right = [&](int a, int b) { return d[n + 1 - a] - d[n + 1 - b]; }; dp[0][0][0][0] = 0; dp[0][0][0][1] = 0; int ans = 0; FOR(l, 0, n) FOR(r, 0, n) { if(l + r > n) break; FOR(k, 0, n) { if(l) { dp[l][r][k][0] = min(dp[l][r][k][0], dp[l - 1][r][k][0] + left(l - 1, l)); dp[l][r][k][0] = min(dp[l][r][k][0], dp[l - 1][r][k][1] + left(0, l) + right(0, r)); } if(r) { dp[l][r][k][1] = min(dp[l][r][k][1], dp[l][r - 1][k][1] + right(r - 1, r)); dp[l][r][k][1] = min(dp[l][r][k][1], dp[l][r - 1][k][0] + left(0, l) + right(0, r)); } } for(int k = n; k >= 1; k--) { if(l && dp[l][r][k - 1][0] <= t[l - 1]) { dp[l][r][k][0] = dp[l][r][k - 1][0]; ans = max(ans, k); } if(r && dp[l][r][k - 1][1] <= t[n - r]) { dp[l][r][k][1] = dp[l][r][k - 1][1]; ans = max(ans, k); } } } cout << ans << "\n"; }
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