답안 #202404

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
202404 2020-02-16T03:40:05 Z gs18115 웜뱃 (IOI13_wombats) C++14
27 / 100
3045 ms 16504 KB
#include"wombats.h"
#include<iostream>
#include<vector>
#include<queue>
#include<algorithm>
#define ep emplace
#define eb emplace_back
#define fi first
#define se second
#define all(x) (x).begin(),(x).end()
#define semicolon ;
#define ryan bear
using namespace std;
typedef long long ll;
typedef pair<int,int>pi;
typedef pair<ll,ll>pl;
const int inf=1e9+7;
const ll INF=1e18+7;
struct node
{
    int l,r;
    int d[200][200];
}tr[1500];
int r,c;
int opt[200][200];
inline void merge(int n,int l,int r)
{
    node&m=tr[n];
    node&x=tr[l];
    node&y=tr[r];
    for(int i=0;i<c;i++)
        for(int j=0;j<c;j++)
            opt[i][j]=-1;
    for(int i=0;i<c;i++)
    {
        int j=0;
        for(int k=0;k<c;k++)
        {
            int&o=opt[i][j]=0;
            for(int k=0;++k<c;)
                if(x.d[i][k]+y.d[k][j]<x.d[i][o]+y.d[o][j])
                    o=k;
        }
    }
    for(int j=0;j<c;j++)
    {
        int i=c-1;
        for(int k=0;k<c;k++)
        {
            int&o=opt[i][j]=0;
            for(int k=0;++k<c;)
                if(x.d[i][k]+y.d[k][j]<x.d[i][o]+y.d[o][j])
                    o=k;
        }
    }
    for(int l=-c;++l<c;)
    {
        for(int i=0;i<c;i++)
        {
            int j=i+l;
            if(j<0||j>=c||opt[i][j]!=-1)
                continue;
            int&o=opt[i][j]=opt[i][j-1];
            for(int k=o;++k<=opt[i+1][j];)
                if(x.d[i][k]+y.d[k][j]<x.d[i][o]+y.d[o][j])
                    o=k;
        }
    }
    for(int i=0;i<c;i++)
        for(int j=0;j<c;j++)
            m.d[i][j]=x.d[i][opt[i][j]]+y.d[opt[i][j]][j];
    return;
}
int dn;
vector<pi>adj[100010];
int d[100010];
inline void dijk(int s)
{
    fill(d,d+dn,inf);
    priority_queue<pi,vector<pi>,greater<pi> >pq;
    pq.ep(d[s]=0,s);
    while(!pq.empty())
    {
        int x=pq.top().se;
        int cd=pq.top().fi;
        pq.pop();
        if(d[x]!=cd)
            continue;
        for(pi&t:adj[x])
            if(d[t.fi]>cd+t.se)
                pq.ep(d[t.fi]=cd+t.se,t.fi);
    }
    return;
}
vector<vector<int> >h,v;
inline void init(int n,int s,int e)
{
    node&x=tr[n];
    dn=(e-s+1)*c;
    for(int i=0;i<dn;i++)
        adj[i].clear();
    for(int i=s;i<=e;i++)
    {
        for(int j=0;j<c-1;j++)
        {
            int cn=i*c-s*c+j;
            adj[cn].eb(cn+1,h[i][j]);
            adj[cn+1].eb(cn,h[i][j]);
        }
    }
    for(int i=s;i<e;i++)
    {
        for(int j=0;j<c;j++)
        {
            int cn=i*c-s*c+j;
            adj[cn].eb(cn+c,v[i][j]);
            adj[cn+c].eb(cn,v[i][j]);
        }
    }
    for(int i=0;i<c;i++)
    {
        dijk(i);
        for(int j=0;j<c;j++)
            x.d[i][j]=d[j+(e-s)*c];
    }
    return;
}
int tct=0,rt;
int init(int s,int e)
{
    int cur=tct++;
    node&x=tr[cur];
    if(e-s<20)
    {
        x.l=x.r=0;
        init(cur,s,e);
        return cur;
    }
    int m=(s+e)/2;
    x.l=init(s,m);
    x.r=init(m,e);
    merge(cur,x.l,x.r);
    return cur;
}
void ch(int n,int s,int e,int r)
{
    if(s>r||e<r)
        return;
    node&x=tr[n];
    if(e-s<20)
    {
        init(n,s,e);
        return;
    }
    int m=(s+e)/2;
    ch(x.l,s,m,r);
    ch(x.r,m,e,r);
    merge(n,x.l,x.r);
    return;
}
void cv(int n,int s,int e,int r)
{
    if(s>r||e<=r)
        return;
    node&x=tr[n];
    if(e-s<20)
    {
        init(n,s,e);
        return;
    }
    int m=(s+e)/2;
    cv(x.l,s,m,r);
    cv(x.r,m,e,r);
    merge(n,x.l,x.r);
    return;
}
void init(int R,int C,int H[5000][200],int V[5000][200])
{
    r=R;
    c=C;
    h.resize(r);
    for(int i=0;i<r;i++)
        for(int j=0;j<c-1;j++)
            h[i].eb(H[i][j]);
    v.resize(r-1);
    for(int i=0;i<r-1;i++)
        for(int j=0;j<c;j++)
            v[i].eb(V[i][j]);
    rt=init(0,r-1);
    return;
}
void changeH(int P,int Q,int W)
{
    h[P][Q]=W;
    ch(rt,0,r-1,P);
    return;
}
void changeV(int P,int Q,int W)
{
    v[P][Q]=W;
    cv(rt,0,r-1,P);
    return;
}
int escape(int V1,int V2)
{
    return tr[rt].d[V1][V2];
}

Compilation message

grader.c: In function 'int main()':
grader.c:15:6: warning: variable 'res' set but not used [-Wunused-but-set-variable]
  int res;
      ^~~
# 결과 실행 시간 메모리 Grader output
1 Correct 12 ms 10360 KB Output is correct
2 Correct 12 ms 10360 KB Output is correct
3 Correct 108 ms 12084 KB Output is correct
4 Correct 13 ms 10360 KB Output is correct
5 Correct 12 ms 10360 KB Output is correct
6 Correct 6 ms 2680 KB Output is correct
7 Correct 6 ms 2680 KB Output is correct
8 Correct 6 ms 2680 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 7 ms 2680 KB Output is correct
2 Correct 7 ms 2680 KB Output is correct
3 Correct 6 ms 2680 KB Output is correct
4 Correct 8 ms 2808 KB Output is correct
5 Correct 7 ms 2808 KB Output is correct
6 Correct 7 ms 2808 KB Output is correct
7 Correct 8 ms 2808 KB Output is correct
8 Incorrect 7 ms 2808 KB Output isn't correct
9 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Incorrect 3025 ms 4348 KB Output isn't correct
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 19 ms 14968 KB Output is correct
2 Correct 20 ms 15100 KB Output is correct
3 Correct 19 ms 15156 KB Output is correct
4 Correct 61 ms 16504 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Incorrect 3028 ms 4448 KB Output isn't correct
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Incorrect 3045 ms 4388 KB Output isn't correct
2 Halted 0 ms 0 KB -