제출 #200368

#제출 시각아이디문제언어결과실행 시간메모리
200368Nordway여행하는 상인 (APIO17_merchant)C++14
0 / 100
27 ms1148 KiB
#include<bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #define x first #define y second #define pb push_back #define mp make_pair #define all(v) v.begin(),v.end() #define sz(v) (int)v.size() #define up_b upper_bound #define low_b lower_bound #define nl '\n' using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef long double ld; typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update>ordered_set; template<class T,int SZ> struct BIT{ T t[SZ]; void upd(int x,T y){ for(int i=x;i<SZ;i=(i|(i+1))){ t[i]+=y; } } T pref(int x){ T res=0; for(int i=x;i>=0;i=(i&(i+1))-1){ res+=t[i]; } return res; } T get(int l,int r){ return pref(r)-pref(l-1); } }; template<class T,int SZ> struct ST{ T t[4*SZ]; void build(T a[],int v,int tl,int tr){ if(tl==tr){ t[v]=a[tl]; return ; } int tm=(tl+tr)/2; build(a,v*2,tl,tm); build(a,v*2+1,tm+1,tr); t[v]=t[v*2]+t[v*2+1]; } void upd(int v,int tl,int tr,int pos,T val){ if(tl==tr){ t[v]+=val; return ; } int tm=(tl+tr)/2; if(pos<=tm)upd(v*2,tl,tm,pos,val); else upd(v*2+1,tm+1,tr,pos,val); t[v]=t[v*2]+t[v*2+1]; } T get(int v,int tl,int tr,int l,int r){ if(tl>r||l>tr)return 0; if(l<=tl&&tr<=r)return t[v]; int tm=(tl+tr)/2; return get(v*2,tl,tm,l,r)+get(v*2+1,tm+1,tr,l,r); } }; const int N=111; const int K=1e3+11; const int W=1e3+11; const int inf=INT_MAX; const ll INF=1e18; const ll mod=1e9+7; const ld EPS=1e-9; const int dx[4]={0,0,1,-1}; const int dy[4]={1,-1,0,0}; vector<pair<int,int>>g[N]; int b[N][K],s[N][K]; ld d[N]; int main(){ ios_base::sync_with_stdio(0); cin.tie(0),cout.tie(0); int n,m,k; cin>>n>>m>>k; for(int i=1;i<=n;i++){ for(int j=1;j<=k;j++){ cin>>b[i][j]>>s[i][j]; } } for(int i=1;i<=m;i++){ int u,v,w; cin>>u>>v>>w; g[u].pb(mp(v,w)); g[v].pb(mp(u,w)); } set<pair<int,int>>q; q.insert(mp(0,1)); d[1]=0; while(!q.empty()){ pair<int,int>p=*q.begin(); q.erase(p); int v=p.y; for(int i=0;i<sz(g[v]);i++){ int to=g[v][i].x; if(d[to]>d[v]+g[v][i].y){ q.erase(mp(d[to],to)); d[to]=d[v]+g[v][i].y; q.insert(mp(d[to],to)); } } } ld ans=0; for(int i=2;i<=n;i++){ for(int j=1;j<=k;j++){ ld cost=s[i][j]-b[1][j]; if(cost<=0)continue; ans=max(ans,cost/(2*d[i])); } } cout<<ans; }
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