제출 #199407

#제출 시각아이디문제언어결과실행 시간메모리
199407mrtsima22수열 (APIO14_sequence)C++17
100 / 100
1501 ms81940 KiB
#pragma GCC optimize "-O3" #pragma GCC optimize("Ofast") #pragma GCC optimization ("unroll-loops") #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> using namespace std; using namespace __gnu_pbds; #define NumberOfOnes __builtin_popcount #define LSOne(S) (S & (-S)) #define ll long long #define two pair<ll,ll> #define twoll pair<ll,ll> #define four pair<two,two> #define pb push_back #define eb emplace_back #define mk make_pair #define y1 y1922 #define INF 1000000000000000000 #define P 1000000007 #define lmax 1000000000 #define nn 1000003 #define ff first.first #define fs first.second #define sf second.first #define ss second.second #define f first #define s second #define vi vector<ll> #define vll vector<ll> #define vtwo vector<two> #define ALL(container) (container).begin(), (container).end() #define sz(container) (ll)(container.size()) #define max(a,b) ((a)>(b)?(a):(b)) #define min(a,b) ((a)<(b)?(a):(b)) #define mid(a,b) (a+b>>1) #define minN 0 #define maxN 10000000 #define na(x) ((x)<P?(x):(x)-P) #define ab(a) (-(a)<(a)?(a):-(a)) #define FAST std::ios::sync_with_stdio(false) #define xRand mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()) #define rnd rng #define IT iterator typedef tree< ll,// aq pair<ll,ll> shegidzlia null_type, less/*_equal*/<ll>,// aqac rb_tree_tag, tree_order_statistics_node_update> ordered_set; // '_equal' mashin ginda roca multiset gchirdeba template<class key, class value,class cmp = std::less<key>> using ordered_map = tree<key, value, cmp, rb_tree_tag, tree_order_statistics_node_update>; ordered_map<ll, ll> my_map; inline ll rin(){ ll x=0,w=1;char ch=getchar(); while ((ch<'0'||ch>'9')&&ch!='-') ch=getchar(); if (ch=='-') w=0,ch=getchar(); while (ch>='0'&&ch<='9') x=(x<<3)+(x<<1)+ch-'0',ch=getchar(); return w?x:-x; } inline ll bin(){ ll x=0;char ch=getchar(); while (ch<'0'||ch>'9') ch=getchar(); while (ch>='0'&&ch<='9') x=(x<<3)+(x<<1)+ch-'0',ch=getchar(); return x; } int v; ll n,k,a[100003],pref[100003],dp[2][100003]; int p[220][100003]; ll f(int l,int r,int k){ ll a=pref[k]-pref[l-1]; ll b=pref[r]-pref[k]; return a*b; } void solve(int l,int r,int optl,int optr){ if(l>r) return; // cout<<l<<" "<<r<<" "<<optl<<" "<<optr<<" "<<v<<endl; int t=v&1; int mid=l+r>>1; twoll opt={-INF,-1}; for(int i=optl;i<=min(mid-1,optr);i++){ opt=max(opt,mk((ll)dp[t^1][i]+f(i+1,n,mid),(ll)i)); } dp[t][mid]=opt.f; p[v][mid]=opt.s; solve(l,mid-1,optl,opt.s); solve(mid+1,r,opt.s,optr); } void bt(int k, int n){ if(!k) return; cout<<n<<" "; bt(k-1,p[k][n]); } int main(){FAST;xRand; cin>>n>>k; for(int i=1;i<=n;i++){ cin>>a[i]; pref[i]=pref[i-1]+a[i]; } for(int i=1;i<=k;i++){ v=i; solve(1,n,0,n); } int g=k; for(int i=1;i<n;i++) if(dp[k&1][i]>=dp[k&1][g]) g=i; cout<<dp[k&1][g]<<endl; bt(k,g); // you should actually read the stuff at the bottom }// /* 7 3 4 1 3 4 0 2 3 */ /* stuff you should look for * ll overflow, array bounds * special cases (n=1?), slow multiset operations * do smth instead of nothing and stay organized * unordered_map, hash_map, scanf, calculate answer instead of ans*K */ /* for(ll i=1;i<=n;i++){ for(ll j=1;j<=k;j++){ for(ll o=0;o<i;o++){ x=(sm[i]-sm[o])*(sm[n]-sm[i])+ dp[o][j-1]; // sm[i]*sm[n]-sm[i]*sm[i]-(sm[n]-sm[i])*sm[o]+dp[o][j-1]; // A -B -C*sm[o]+dp[o][j-1] if(x>=dp[i][j]){ dp[i][j]=x; p[i][j]=o; } } } } */ // https://cp-algorithms.com/geometry/convex_hull_trick.html // https://cp-algorithms.com/dynamic_programming/divide-and-conquer-dp.html /* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * */

컴파일 시 표준 에러 (stderr) 메시지

sequence.cpp:3:0: warning: ignoring #pragma GCC optimization [-Wunknown-pragmas]
 #pragma GCC optimization ("unroll-loops")
 
sequence.cpp: In function 'void solve(int, int, int, int)':
sequence.cpp:82:11: warning: suggest parentheses around '+' inside '>>' [-Wparentheses]
  int mid=l+r>>1;
          ~^~
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