이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#pragma GCC optimize ("O2")
#pragma GCC optimize ("unroll-loops")
//#pragma GCC optimize("no-stack-protector,fast-math")
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<pii, int> piii;
typedef pair<ll, ll> pll;
#define debug(x) cerr<<#x<<'='<<(x)<<endl;
#define debugp(x) cerr<<#x<<"= {"<<(x.first)<<", "<<(x.second)<<"}"<<endl;
#define debug2(x, y) cerr<<"{"<<#x<<", "<<#y<<"} = {"<<(x)<<", "<<(y)<<"}"<<endl;
#define debugv(v) cerr<<#v<<" : ";for (auto x:v) cerr<<x<<' ';cerr<<endl;
#define all(x) x.begin(), x.end()
#define pb push_back
#define kill(x) return cout<<x<<'\n', 0;
const ld eps=1e-7;
const int inf=1000000010;
const ll INF=10000000000000010LL;
const int mod = 1000000007;
const int MAXN = 100010, SGM=26;
int n, m, k, u, v, x, y, t, a, b, ans1=SGM, ans2, L, R;
int last[MAXN][SGM];
bool mark[SGM];
string S;
void upd(int l, int r, int t){
if (t*ans2>(r-l+1)*ans1) return ;
ans1=t;
ans2=r-l+1;
R=r;
L=l;
}
int main(){
ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
//freopen("input.txt", "r", stdin);
//freopen("output.txt", "w", stdout);
cin>>n>>S;
S="."+S;
for (int i=1; i<=n; i++){
memcpy(last[i], last[i-1], sizeof(last[i]));
last[i][S[i]-'a']=i;
}
for (int i=1; i<=n; i++){
memset(mark, 0, sizeof(mark));
int cnt=1;
mark[S[i]-'a']=1;
int l=i;
upd(l, i, cnt);
while (l){
int nl=0;
for (int j=0; j<SGM; j++) if (!mark[j]) nl=max(nl, last[l][j]);
l=nl;
upd(l+1, i, cnt);
mark[S[l]-'a']=1;
cnt++;
}
}
cout<<L<<' '<<R<<'\n';
return 0;
}
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