이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <algorithm>
#include <cmath>
#include <vector>
#include <set>
#include <map>
#include <unordered_set>
#include <unordered_map>
#include <queue>
#include <ctime>
#include <cassert>
#include <complex>
#include <string>
#include <cstring>
#include <chrono>
#include <random>
#include <queue>
#include <bitset>
#include <stack>
#include <iomanip>
using namespace std;
#define all(x) x.begin(), x.end()
typedef vector <int> vi;
typedef pair<int,int> ii;
typedef long long ll;
typedef long double ld;
const int mod = 1e9 + 7;
const ll inf = 3e18 + 5;
int add(int a, int b) { return (a += b) < mod ? a : a - mod; }
int mul(int a, int b) { return 1LL * a * b % mod; }
int sub(int a, int b) { return (a -= b) < 0 ? a + mod : a; }
int ctz(int x) { return __builtin_ctz(x); }
int clz(int x) { return __builtin_clz(x); }
int main(){
ios_base::sync_with_stdio(false); cin.tie(0);
#ifdef LOCAL
freopen("input.txt", "r", stdin);
freopen("output.txt", "w", stdout);
#endif
int n;
string s;
cin >> n >> s;
ld res = 2.0;
int A = 0, B = 0;
for(int x = 1; x <= 26; x++){
vi has(26);
int cnt = 0;
int r = 0;
for(int i = 0; i < n; i++){
while(r < n && cnt <= x){
if(!has[s[r] - 'a']){
if(cnt + 1 > x) break;
cnt++;
}
has[s[r++] - 'a']++;
}
//cout << i << " -> " << r << endl;
if((ld) x / (ld) (r - i) < res){
res = (ld) x / (ld) (r - i);
A = i;
B = r - 1;
}
if(has[s[i] - 'a'] == 1){
cnt--;
}
has[s[i] - 'a']--;
}
}
cout << A + 1 << " " << B + 1;
}
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