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답안 #197596

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
197596 2020-01-21T20:59:56 Z stefdasca Watering can (POI13_kon) C++14
40 / 100
 4000 ms 6152 KB 
#include<bits/stdc++.h>
#include "koninc.h"
using namespace std;

const int MAXN = 300001, rad = 550;

int N, K, v[MAXN+5], done = 300000;

int buk[MAXN+5], L[1012], R[1012], ad[1012], nrbuk, aans[1012];

unordered_map<int, int> ans[602];

void proc(int bk, int LL, int RR)
{
    ans[bk].clear();
    for(int j = LL; j <= RR; ++j)
        v[j]++;
    for(int j = L[bk]; j <= R[bk]; ++j)
    {
        v[j] += ad[bk];
        if(v[j] >= K)
            ans[bk][0]++;
        else
            if(K - v[j] <= done)
                ans[bk][K - v[j]]++;
    }
    ad[bk] = 0;
    aans[bk] = ans[bk][0];
}

void inicjuj(int n, int k, int *D)
{
    N = n, K = k;
    for(int i = 0; i < n; ++i)
        v[i] = D[i];
    for(int i = 0; i < n; ++i)
    {
        if(i % rad == 0)
            ++nrbuk, L[nrbuk] = i;
        R[nrbuk] = i;
        buk[i] = nrbuk;
    }
    for(int i = 0; i <= nrbuk; ++i)
        proc(i, 1, 0);
}

void podlej(int a, int b)
{
    int fini = R[buk[a]];
    int ax = buk[a];
    proc(ax, a, min(b, fini));
    a = min(b, fini) + 1;
    while(a < N && R[buk[a]] <= b)
    {
        ++ad[buk[a]];
        if(ans[buk[a]].find(ad[buk[a]]) != ans[buk[a]].end())
            aans[buk[a]] = aans[buk[a]] + ans[buk[a]][ad[buk[a]]];
        a = R[buk[a]] + 1;
    }
    if(a <= b)
    {
        fini = R[buk[a]];
        ax = buk[a];
        proc(ax, a, b);
    }
    --done;
}

int dojrzale(int a, int b)
{
    int fini = R[buk[a]];
    int qans = 0;
    proc(buk[a], 1, 0);
    while(a <= b && a <= fini)
    {
        if(v[a] >= K)
            ++qans;
        ++a;
    }
    while(a < N && R[buk[a]] <= b)
        qans += aans[buk[a]], a = R[buk[a]] + 1;
    if(a <= b)
    {
        proc(buk[a], 1, 0);
        fini = R[buk[a]];
        while(a <= b && a <= fini)
        {
            if(v[a] >= K)
                ++qans;
            ++a;
        }
    }
    --done;
    return qans;
}

Subtask #1
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 376 KB Output is correct
2 Correct 2 ms 376 KB Output is correct
3 Correct 2 ms 376 KB Output is correct

Subtask #2
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 28 ms 376 KB Output is correct
2 Correct 117 ms 504 KB Output is correct
3 Correct 2 ms 376 KB Output is correct

Subtask #3
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1055 ms 1228 KB Output is correct
2 Correct 1012 ms 844 KB Output is correct
3 Correct 1268 ms 1120 KB Output is correct

Subtask #3
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1249 ms 1236 KB Output is correct
2 Correct 276 ms 1016 KB Output is correct
3 Correct 1606 ms 1320 KB Output is correct

Subtask #5
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3204 ms 3212 KB Output is correct
2 Execution timed out 4008 ms 2720 KB Time limit exceeded
3 Halted 0 ms 0 KB -

Subtask #6
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 4045 ms 3836 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #7
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 4100 ms 2832 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #8
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 4101 ms 3860 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #9
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3295 ms 5456 KB Output is correct
2 Correct 2071 ms 5688 KB Output is correct
3 Execution timed out 4030 ms 5412 KB Time limit exceeded

Subtask #10
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3110 ms 5568 KB Output is correct
2 Correct 3910 ms 6152 KB Output is correct
3 Execution timed out 4088 ms 4376 KB Time limit exceeded