이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define ld double
#define sz(x) (int)x.size()
#define all(x) x.begin(),x.end()
#define pb emplace_back
#define X first
#define Y second
const int N = 2005;
typedef pair<int,int> ii;
int a[N][N];
int f[N][N];
int s[N][N];
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
int n; cin >> n;
int m; cin >> m;
int mx = 1, my = 1;
int Mx = 1, My = 1;
for(int i = 1 ; i <= n ; ++i)
for(int j = 1 ; j <= m ; ++j) {
cin >> a[i][j];
if (a[mx][my] > a[i][j]) mx = i, my = j;
if (a[Mx][My] < a[i][j]) Mx = i, My = j;
}
auto check = [&](int lx,int rx,int ly,int ry,int dx,int dy) {
for(int i = lx ; i != rx ; i += dx)
for(int j = ly ; j != ry ; j += dy) {
int area = f[i][j] % 2;
area += s[i][j - dy];
area += s[i - dx][j];
area -= s[i - dx][j - dy];
if (area == (abs(i - lx) + 1) * (abs(j - ly) + 1))
s[i][j] = area;
else {
s[i][j] = area - 1;
if (f[i][j] & 2) continue;
else return 0;
}
}
return 1;
};
int L = 0;
int R = a[Mx][My] - a[mx][my];
while(L < R) {
int M = (L + R) / 2;
for(int i = 1 ; i <= n ; ++i)
for(int j = 1 ; j <= m ; ++j) {
f[i][j] = 0;
if (a[i][j] - a[mx][my] <= M) f[i][j] ^= 1;
if (a[Mx][My] - a[i][j] <= M) f[i][j] ^= 2;
if (f[i][j] == 0)
goto out;
}
if (check(1,n + 1,1,m + 1,1,1)) {
R = M;
continue;
}
if (check(n,0,1,m + 1,-1,1)) {
R = M;
continue;
}
if (check(1,n + 1,m,0,1,-1)) {
R = M;
continue;
}
if (check(n,0,m,0,-1,-1)) {
R = M;
continue;
}
out:;
L = M + 1;
}
cout << L << endl;
}
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