Submission #1925

#	Time	Username	Problem	Language	Result	Execution time	Memory
1925		1sm2000	토마토 (3차원) (KOI13_tomato3D)	C11	12 / 20	144 ms	24616 KiB

cc

#include <stdio.h> 
int Queuex[500001], Queuey[500001], Queuez[500001], Time[500001], check=0, checking=0; 
int front=1, rear=1, tomato[101][201][101], visit[101][201][101]; 
int Dirx[8]={0, -1, 1, 0, 0, 0, 0}, Diry[8]={0, 0, 0, -1, 1, 0, 0}, Dirz[8]={0, 0, 0, 0, 0, -1, 1}; 
void push(int a, int b, int c, int t) 
{ 
    Queuex[rear] = a; 
    Queuey[rear] = b; 
    Queuez[rear] = c; 
    Time[rear] = t; 
    rear++; 
} 
int Qx() 
{ 
    return Queuex[front]; 
} 
int Qy() 
{ 
    return Queuey[front]; 
} 
int Qz() 
{ 
    return Queuez[front++]; 
} 
int main() 
{ 
    //freopen("input.txt", "r", stdin); 
    //freopen("output.txt", "w", stdout); 
    int n, k, l, tle=0, res=0, tmp=0; 
    int i, j, a; 
    int x1=0, x2=0, x3=0; 
    scanf("%d %d %d", &n, &k, &l); 
    tle=n*k*l; 
    tmp = n; 
    n = k; 
    k = tmp; 
    for (i=1; i<=l; i++) 
    { 
        for (j=1; j<=n; j++) 
        { 
            for (a=1; a<=k; a++) 
            { 
                scanf("%d", &tomato[i][j][a]); 
                if (tomato[i][j][a] != 0) 
                { 
                    check++; 
                    tle--; 
                } 
                if (tomato[i][j][a] == 1) 
                { 
                    push(i, j, a, 0); 
                    visit[i][j][a] = 1; 
                } 
            } 
        } 
    } 
  
    while (front != rear) 
    { 
        x1=Qx(); 
        x2=Qy(); 
        x3=Qz(); 
        res++; 
        for (i=1; i<=6; i++) 
        { 
            if (tomato[x1+Dirx[i]][x2+Diry[i]][x3+Dirz[i]] == 0 && visit[x1+Dirx[i]][x2+Diry[i]][x3+Dirz[i]] == 0 
                && x1+Dirx[i] > 0 && x1+Dirx[i] <= l && x2+Diry[i] > 0 && x2+Diry[i] <= n && x3+Dirz[i] > 0 && x3+Dirz[i] <= k) 
            { 
                tle--; 
                tomato[x1+Dirx[i]][x2+Diry[i]][x3+Dirz[i]] = 1; 
                push(x1+Dirx[i], x2+Diry[i], x3+Dirz[i], Time[res]+1); 
                visit[x1+Dirx[i]][x2+Diry[i]][x3+Dirz[i]] = 1; 
            } 
        } 
        if (tle == 0) break; 
    } 
  
    for (i=1; i<=l; i++) 
    { 
        for (j=1; j<=n; j++) 
        { 
            for (a=1; a<=k; a++) 
            { 
                if (tomato[i][j][a] == -1 || tomato[i][j][a] == 1) 
                { 
                    checking++; 
                } 
            } 
        } 
    } 
    if (n*k*l == checking) printf("%d", Time[rear-1]); 
    else printf("-1"); 
    return 0; 
}

• Subtask 1: 2 / 2
• Subtask 2: 2 / 2
• Subtask 3: 2 / 2
• Subtask 4: 2 / 2
• Subtask 5: 2 / 2
• Subtask 6: 2 / 2
• Subtask 7: 0 / 2
• Subtask 8: 0 / 2
• Subtask 9: 0 / 2
• Subtask 10: 0 / 2