제출 #19248

#제출 시각아이디문제언어결과실행 시간메모리
19248kaTkaHr창문 (kriii4_C)C++14
3 / 100
0 ms1084 KiB
#include <stdio.h>
#include <algorithm>
#include <map>

using namespace std;

typedef long long ll;

const int MX = 105, MM = 1000000007;

ll rv(ll A){
	ll R = 1, B = MM-2;
	while(B){
		if( B&1 ) R = R * A % MM;
		A = A * A % MM; B /= 2;
	}
	return R;
}

struct frac{
	ll A, B;
	frac(ll a, ll b){
		A = (a%MM+MM) % MM;
		B = (b%MM+MM) % MM;
	}
	frac(){A = 0, B = 1;}
	frac operator+ (const frac &l)const{
		return frac((A * l.B + B * l.A) % MM, B * l.B % MM);
	}
	frac operator*(const frac &l)const{
		return frac(A*l.A % MM, B*l.B % MM);
	}
	frac operator/(const frac &l)const{
		return frac(A*l.B % MM, B*l.A % MM);
	}
	frac operator- (const frac &l)const{
		return frac((A*l.B - B*l.A%MM + MM) % MM, B*l.B % MM);
	}
	ll v(){ return A * rv(B) % MM; }
};

int main()
{
	ll H, W;
	scanf("%lld%lld", &H, &W);
	frac w = frac(0, 1), h = frac(0, 1), t = frac(0, 1);
	w = frac(W, 2) * frac(W+1, 1) * frac(W+1, 1) - frac(W, 2) * frac(W+1, 3) * frac(2*W+1, 1);
	h = frac(H, 2) * frac(H+1, 1) * frac(H+1, 1) - frac(H, 2) * frac(H+1, 3) * frac(2*H+1, 1);
	t = frac(2, H) * frac(1, H+1) * frac(2, W) * frac(1, W+1);
	printf("%lld\n", (frac(9, 1)*w*h*t).v());
}
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