답안 #18781

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
18781 2016-02-15T05:58:56 Z pichulia 여왕벌 (KOI15_queen) C++14
68 / 100
5000 ms 524288 KB
#include<stdio.h>
#include<unordered_map>
#include<set>
#include<vector>
#include<algorithm>
using namespace std;
int m, n;
char a[701][701][3][3][3];
int tel_011[701][701];
int tel_022[701][701];
int tel_122[701][701];
int cel_001[701][701];
int cel_002[701][701];
int cel_112[701][701];
int r[701][701];
int c[701][701];
char x[999];
vector<pair<int, pair<int, int>>> b1;
vector<pair<int, pair<int, int>>> b2;
vector<pair<int, pair<int, int>>> b3;
int m1, m2, m3;


unordered_map<int, int> s[701];
unordered_map<int, vector<int>> v[701];
__inline int hashing(int si, int p, int q)
{
	return (si<<20)|(p<<10)|q;
}

void process(int i0, int i1, int i2, int aaa)
{
	int i, j, k, l;
	int si,ti;
	int hi,ii;
	int p,q;
	// p = start of 1, q = start of 2
	if (i0 + i1 < n)
	{
		p = 0; q = 0;
	}
	else if (i0 < n)
	{
		p = 0; q = n - i2;
	}
	else
	{
		p = i0 - n + 1; q = n - i2;
	}
	hi = hashing(0, p, q);
	if(s[0].count(hi)){
		s[0][hi]+=aaa;
		return;
	}
	else
		s[0][hi] = aaa;
	for (i = 1; i < n; ++i)
	{
		int np, nq;
		np = p;
		nq = q;
		
		if (i0 + i1 < (n - i))si = 2;
		else if (i0 < (n - i)) si = 1;
		else si = 0;

		ii = hi;
		hi = hashing(si, p, q);

		v[i-1][ii].push_back(hi);
		if(s[i].count(hi))
		{
			return;
		}
		s[i][hi] = 0;

		if (si == 0)
		{
			if (p> 0) // 0 0 0 x x x
			{
				if (p != q) // 0 0 0 1 1 1 2 2 2
				{
					if (a[i][p][0][0][1] == 1)
					{
						np = p;
						if (a[i][q][1][1][2] == 2)
						{
							nq = q;
						}
						else
							nq = tel_122[i][q];
					}
					else
					{
						j = tel_011[i][p];
						if (j < q)
						{
							np = j;
							if (a[i][q][1][1][2] == 2)
							{
								nq = q;
							}
							else
							{
								nq = tel_122[i][q];
							}

						}
						else
						{
							j = q;
							// 0 0 1 1 2 2
							// 0 0 0 0 ?
							if (j < n && a[i][j][0][1][2] == 1)
							{
								np = j;
								nq = tel_122[i][q];
							}
							else
							{
								if (a[i][q][0][1][2] == 2)
								{
									nq = q;
									np = nq;
								}
								else
								{
									nq = tel_022[i][q];
									np = nq;
								}
							}

						}
					}
				}
				else // 0 0 0 2 2 2
				{
					if (a[i][q][0][0][2] == 2)
					{
						nq = q;
						np = nq;
					}
					else
					{
						nq = tel_022[i][q];
						np = nq;
					}
				}
			}
			else if (q > 0) // 1 1 1 x x x
			{
				j = tel_011[i][0];
				if (j < q)
				{
					np = j;
					if (a[i][q][1][1][2] == 2)
					{
						nq = q;
					}
					else
					{
						nq = tel_122[i][q];
					}
				}
				else
				{
					j = q;
					if (j < n && a[i][j][0][1][2] == 1)
					{
						np = j;
						nq = tel_122[i][q];
					}
					else
					{
						if (a[i][q][0][1][2] == 2)
						{
							nq = q;
							np = nq;
						}
						else
						{
							nq = tel_022[i][q];
							np = nq;
						}
					}
				}
			}
			else // 2 2 2 ... 
			{
				nq = tel_022[i][0];
				np = nq;
			}
		} // end of si == 0
		else if (si == 1)
		{
			np = 0;
			if (q > 0) // 1 1 1 x x x
			{
				if (a[i][q][1][1][2] == 2)
				{
					nq = q;
				}
				else
				{
					nq = tel_122[i][q];
				}
			}
			else // 2 2 2 x x x
			{
				nq = tel_122[i][0];
			}
		} // end of si == 1
		else
		{
			np = nq = 0;
		} // end of si == 2
		p = np;
		q = nq;
	}
	ii = hi;
	hi = hashing(0, p, q);

	v[i-1][ii].push_back(hi);
	s[i][hi] = 0;
}

void process3(int i0, int i1, int i2, int aaa)
{
	int i, j, k, l;
	int si,ti;
	int hi,ii;
	int p,q;
	// p = start of 1, q = start of 2
	p = i0 - n + 1; q = n - i2;
	
	hi = hashing(0, p, q);
	if(s[0].count(hi)){
		s[0][hi]+=aaa;
		return;
	}
	else
		s[0][hi] = aaa;
	for (i = 1; i < n; ++i)
	{
		int np, nq;
		np = p;
		nq = q;
		si = 0;

		ii = hi;
		hi = hashing(si, p, q);

		v[i-1][ii].push_back(hi);
		if(s[i].count(hi))
		{
			return;
		}
		s[i][hi] = 0;

		if (p != q) // 0 0 0 1 1 1 2 2 2
		{
			if (a[i][p][0][0][1] == 1)
			{
				np = p;
				if (a[i][q][1][1][2] == 2)
				{
					nq = q;
				}
				else
					nq = tel_122[i][q];
			}
			else
			{
				j = tel_011[i][p];
				if (j < q)
				{
					np = j;
					if (a[i][q][1][1][2] == 2)
					{
						nq = q;
					}
					else
					{
						nq = tel_122[i][q];
					}

				}
				else
				{
					j = q;
					// 0 0 1 1 2 2
					// 0 0 0 0 ?
					if (j < n && a[i][j][0][1][2] == 1)
					{
						np = j;
						nq = tel_122[i][q];
					}
					else
					{
						if (a[i][q][0][1][2] == 2)
						{
							nq = q;
							np = nq;
						}
						else
						{
							nq = tel_022[i][q];
							np = nq;
						}
					}

				}
			}
		}
		else // 0 0 0 2 2 2
		{
			if (a[i][q][0][0][2] == 2)
			{
				nq = q;
				np = nq;
			}
			else
			{
				nq = tel_022[i][q];
				np = nq;
			}
		}
		
		p = np;
		q = nq;
	}
	ii = hi;
	hi = hashing(0, p, q);

	v[i-1][ii].push_back(hi);
	s[i][hi] = 0;
}
void process2(int i0, int i1, int i2,int aaa)
{
	int i, j, k, l;
	int si,ti;
	int hi,ii;
	int p,q;
	// p = start of 1, q = start of 0
	p = n - i0 - i1; q = n - i0;
	hi = hashing(0, p, q);
	if(s[0].count(hi)){
		s[0][hi]+=aaa;
		return;
	}
	else
		s[0][hi] = aaa;
	for (i = 1; i < n; ++i)
	{
		int np, nq;
		np = p;
		nq = q;
		si = 2;

		ii = hi;
		hi = hashing(si, p, q);

		v[i-1][ii].push_back(hi);
		if(s[i].count(hi))
		{
			return;
		}
		s[i][hi] = 0;

		if (p != q) // 2 2 2 1 1 1 0 0 0
		{
			if (a[p][i][1][2][2] == 1)
			{
				np = p;
				if (a[q][i][0][1][1] == 0)
				{
					nq = q;
				}
				else
					nq = cel_001[q][i];
			}
			else
			{
				j = cel_112[p][i];
				if (j < q)
				{
					np = j;
					if (a[q][i][0][1][1] == 0)
					{
						nq = q;
					}
					else
					{
						nq = cel_001[q][i];
					}
				}
				else
				{
					j = q;
					// 2 2 1 1 0 0
					// 2 2 2 2 ?
					if (j < n && a[j][i][0][1][2] == 1)
					{
						np = j;
						nq = cel_001[q][i];
					}
					else
					{
						if (a[q][i][0][1][2] == 0)
						{
							nq = q;
							np = nq;
						}
						else
						{
							nq = cel_002[q][i];
							np = nq;
						}
					}

				}
			}
		}
		else // 2 2 2 0 0 0
		{
			if (a[q][i][0][2][2] == 0)
			{
				nq = q;
				np = nq;
			}
			else
			{
				nq = cel_002[q][i];
				np = nq;
			}
		}
		p = np;
		q = nq;
	}
	ii = hi;
	hi = hashing(0, p, q);

	v[i-1][ii].push_back(hi);
	s[i][hi] = 0;
}
void precess()
{
	int i, j, k, l;
	for (i = 1; i < n; ++i)
	{
		for (j = 0; j < n;)
		{
			for (k = j+1; k < n; ++k)
			{
				if (a[i][k][0][1][1] == 1)
					break;
			}
			for (l = j; l < k; ++l)
			{
				tel_011[i][l] = k;
			}
			j = k;
		}
		for (j = 0; j < n;)
		{
			for (k = j+1; k < n; ++k)
			{
				if (a[i][k][0][2][2] == 2)
					break;
			}
			for (l = j; l < k; ++l)
			{
				tel_022[i][l] = k;
			}
			j = k;
		}
		for (j = 0; j < n;)
		{
			for (k = j+1; k < n; ++k)
			{
				if (a[i][k][1][2][2] == 2)
					break;
			}
			for (l = j; l < k; ++l)
			{
				tel_122[i][l] = k;
			}
			j = k;
		}
		tel_011[i][n] = n;
		tel_022[i][n] = n;
		tel_122[i][n] = n;
	}
	for (i = 1; i < n; ++i)
	{
		for (j = 0; j < n;)
		{
			for (k = j+1; k < n; ++k)
			{
				if (a[k][i][0][0][1] == 0)
					break;
			}
			for (l = j; l < k; ++l)
			{
				cel_001[l][i] = k;
			}
			j = k;
		}
		for (j = 0; j < n;)
		{
			for (k = j+1; k < n; ++k)
			{
				if (a[k][i][0][0][2] == 0)
					break;
			}
			for (l = j; l < k; ++l)
			{
				cel_002[l][i] = k;
			}
			j = k;
		}
		for (j = 0; j < n;)
		{
			for (k = j+1; k < n; ++k)
			{
				if (a[k][i][1][1][2] == 1)
					break;
			}
			for (l = j; l < k; ++l)
			{
				cel_112[l][i] = k;
			}
			j = k;
		}
		cel_001[n][i] = n;
		cel_002[n][i] = n;
		cel_112[n][i] = n;
	}
	for(i=1; i<n; i++)
	{
		a[i][n][0][1][2] = 2;
		a[i][n][1][1][2] = 2;
		a[i][n][0][0][2] = 2;
		a[n][i][0][1][2] = 0;
		a[n][i][0][1][1] = 0;
		a[n][i][0][2][2] = 0;
	}
}
int main()
{
	scanf("%d %d", &n, &m);
	int i, j, k, l;
	for (i = 1; i < n; ++i)
		for (j = 1; j < n; ++j)
		{
			scanf("%s", x);
			k = 0;
			for (char ii = 0; ii < 3; ++ii)
				for (char jj = 0; jj < 3; ++jj)
					for (char kk = 0; kk < 3; ++kk)
					{
						char cc = x[k++];
						if (cc == 'L')
						{
							cc = ii;
						}
						else if (cc == 'D')
						{
							cc = jj;
						}
						else
						{
							cc = kk;
						}
						a[i][j][ii][jj][kk] = cc;
					}
		}
	precess();
	int ccnt = 0;
	{
		m1=m2=m3=0;
		for(i=0; i<m; ++i)
		{
			int i0, i1, i2;
			scanf("%d %d %d", &i0, &i1, &i2);
          
			if(i2>=n)
			{
				b2.push_back(pair<int, pair<int, int>>(i0, pair<int, int>(i1, i2)));
				m2++;
			}
			else if (i0 >= n)
			{
				b3.push_back(pair<int, pair<int, int>>(i0, pair<int, int>(i1, i2)));
				m3++;
			}
			else
			{
				b1.push_back(pair<int, pair<int, int>>(i0, pair<int, int>(i1, i2)));
				m1++;
			}
		}
		sort(b1.begin(), b1.end());
		sort(b2.begin(),b2.end());
		sort(b3.begin(),b3.end());
      
		for(i=0;i<m1;)
		{
			for(l=0; l<=n;++l)
			{
				s[l].clear();
				v[l].clear();
			}
			for(j=i+1;j<m1;++j)
				if(b1[i].first != b1[j].first)
					break;
			for(k=i;k<j;)
			{
				for(l=k+1; l<j; ++l)
				{
					if(b1[k].second != b1[l].second)
						break;
				}
				process(b1[k].first, b1[k].second.first, b1[k].second.second, l-k);
				k=l;
			}
			i = j;
			for(j=0;j<=n;++j)
			{
				for(auto x : s[j])
				{
					int xi = x.first;
					int xp = (xi&(0xffc00))>>10;
					int xq = xi&(0x3ff);
		//			printf("%d %d %d  %d\n",j, xp, xq, x.second);
					if(j>0)
					{
						r[j-1][xp]+=x.second;
						r[j-1][xq]+=x.second;
					}
					for(auto y : v[j][xi])
					{
						s[j+1][y]+=x.second;
					}
				}
			}
		}
//		for(j=0; j<m3; j+=em3)
		{
			for(l=0; l<=n;++l)
			{
				s[l].clear();
				v[l].clear();
			}
			int ee = m3;
			for(i=0; i<ee;)
			{
				for(l=i+1; l<ee; ++l)
				{
					if(b3[i] != b3[l])
						break;
				}
				process3(b3[i].first, b3[i].second.first, b3[i].second.second, l-i);
				i=l;
			}
			for(l=0;l<=n;++l)
			{
				for(auto x : s[l])
				{
					int xi = x.first;
					int xp = (xi&(0xffc00))>>10;
					int xq = xi&(0x3ff);
			//		printf("%d %d %d  %d\n",j, xp, xq, x.second);
					if(l>0)
					{
						r[l-1][xp]+=x.second;
						r[l-1][xq]+=x.second;
					}
					for(auto y : v[l][xi])
					{
						s[l+1][y]+=x.second;
					}
				}
			}
		}
	//	for(j=0; j<m2; j+=em2)
		{
			for(l=0; l<=n;++l)
			{
				s[l].clear();
				v[l].clear();
			}
			int ee = m2;
			for(i=0; i<ee;)
			{
				for(l=i+1; l<ee; ++l)
				{
					if(b2[i] != b2[l])
						break;
				}
				process2(b2[i].first, b2[i].second.first, b2[i].second.second, l-i);
				i=l;
			}
			for(l=0;l<=n;++l)
			{
				for(auto x : s[l])
				{
					int xi = x.first;
					int xp = (xi&(0xffc00))>>10;
					int xq = xi&(0x3ff);
			//		printf("%d %d %d  %d\n",j, xp, xq, x.second);
					if(l>0)
					{
						c[xp][l-1]-=x.second;
						c[xq][l-1]-=x.second;
					}
					for(auto y : v[l][xi])
					{
						s[l+1][y]+=x.second;
					}
				}
			}
		}
		for (i = 0; i < n; ++i)
		{
			for (j = 1; j < n; ++j)
			{
				r[i][j] += r[i][j-1];
			}
			c[0][i] += m2 * 2;
			for(j=1; j<n; ++j)
			{
				c[j][i] += c[j-1][i];
			}
		}
		for(i=0; i<n; ++i, printf("\n"))
			for(j=0; j<n; ++j)
				printf("%d ",r[i][j] + c[i][j] + 1);
	}
}
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 30116 KB Output is correct
2 Correct 0 ms 30116 KB Output is correct
3 Correct 3 ms 30116 KB Output is correct
4 Correct 10 ms 30116 KB Output is correct
5 Correct 48 ms 30116 KB Output is correct
6 Correct 42 ms 30116 KB Output is correct
7 Correct 38 ms 30116 KB Output is correct
8 Correct 100 ms 30116 KB Output is correct
9 Correct 107 ms 30116 KB Output is correct
10 Correct 208 ms 30116 KB Output is correct
11 Correct 293 ms 30116 KB Output is correct
12 Correct 274 ms 30116 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 30340 KB Output is correct
2 Correct 83 ms 32188 KB Output is correct
3 Correct 147 ms 33740 KB Output is correct
4 Correct 421 ms 32452 KB Output is correct
5 Correct 350 ms 35952 KB Output is correct
6 Correct 342 ms 31612 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 30404 KB Output is correct
2 Correct 29 ms 31852 KB Output is correct
3 Correct 240 ms 37528 KB Output is correct
4 Correct 1737 ms 64012 KB Output is correct
5 Correct 1502 ms 58156 KB Output is correct
6 Correct 1445 ms 57964 KB Output is correct
7 Correct 1972 ms 84976 KB Output is correct
8 Correct 2790 ms 106232 KB Output is correct
9 Correct 2808 ms 133948 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 3694 ms 100244 KB Output is correct
2 Execution timed out 5000 ms 47856 KB Program timed out
3 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 30116 KB Output is correct
2 Correct 2 ms 30116 KB Output is correct
3 Correct 0 ms 30116 KB Output is correct
4 Correct 3 ms 30116 KB Output is correct
5 Correct 356 ms 51824 KB Output is correct
6 Correct 358 ms 51824 KB Output is correct
7 Correct 348 ms 51632 KB Output is correct
8 Correct 384 ms 51824 KB Output is correct
9 Memory limit exceeded 3936 ms 524288 KB Memory limit exceeded
10 Halted 0 ms 0 KB -