이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <string.h>
#include <vector>
using namespace std;
#define endl '\n'
#define pi pair<int, int>
#define pii pair<pi, pi>
struct segTree{
int l, r;
segTree *left = 0, *right = 0;
long val = 0;
segTree(int a, int b){
l = a;
r = b;
}
void add(int x, int v){
if(l == r){
val += v;
return;
}
int mid = (l + r) / 2;
if(x <= mid){
if(!left) left = new segTree(l, mid);
left->add(x, v);
}else{
if(!right) right = new segTree(mid + 1, r);
right->add(x, v);
}
val = (left ? left->val : 0) + (right ? right->val : 0);
}
long qry(int a, int b){
if(r < a || b < l) return 0;
if(a <= l && r <= b) return val;
return (left ? left->qry(a, b) : 0) + (right ? right->qry(a, b) : 0);
}
};
const int maxn = 300001;
struct BIT{
segTree *bit[maxn];
BIT(){
memset(bit, 0, sizeof(bit));
}
void add(int x, int y, int v){
for(x++; x < maxn; x += x & -x){
if(!bit[x]) bit[x] = new segTree(0, maxn);
bit[x]->add(y, v);
}
}
int qry(int x, int y, int Y){
int ret = 0;
for(x++; x; x -= x & -x) if(bit[x]) ret += bit[x]->qry(y, Y);
return ret;
}
int qry(int x, int X, int y, int Y){
return qry(X, y, Y) - qry(x - 1, y, Y);
}
};
int n, q;
pi a[maxn];
pii qry[maxn];
vector<int> v;
BIT bit;
int ans[maxn];
int id(int x){
return lower_bound(v.begin(), v.end(), x, greater<int>()) - v.begin();
}
int main(){
ios::sync_with_stdio(false);
cin.tie(NULL);
cin >> n >> q;
for(int i = 0; i < n; i++) cin >> a[i].first >> a[i].second;
for(int i = 0; i < q; i++){
cin >> qry[i].first.first >> qry[i].second.first >> qry[i].second.second;
qry[i].first.second = i;
v.push_back(qry[i].first.first);
v.push_back(qry[i].second.first);
v.push_back(qry[i].second.second);
}
sort(a, a + n, greater<pi>());
sort(qry, qry + q, greater<pii>());
sort(v.begin(), v.end(), greater<int>());
v.erase(unique(v.begin(), v.end()), v.end());
for(int i = 0, j = 0; i < q; i++){
for(; j < n && a[j].first >= qry[i].first.first; j++) bit.add(id(a[j].second), id(a[j].first + a[j].second), 1);
ans[qry[i].first.second] = bit.qry(id(qry[i].second.first), 0, id(qry[i].second.second));
}
for(int i = 0; i < q; i++) cout << ans[i] << endl;
return 0;
}
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