이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//#pragma GCC optimize("Ofast")
//#pragma GCC target("avx,avx2,fma")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#define ordered_set tree <pair <int, int>, null_type, less <pair <int, int> >, rb_tree_tag, tree_order_statistics_node_update>
using namespace __gnu_pbds;
#define ll long long
#define db double
#define pb push_back
#define ppb pop_back
#define fi first
#define se second
#define mp make_pair
#define size(x) (int)(x).size()
#define all(x) (x).begin(), (x).end()
#define low_b lower_bound
#define endl "\n"
//#define int long long
using namespace std;
void dout() {
cerr << endl;
}
template <typename Head, typename... Tail>
void dout(Head H, Tail... T) {
cerr << H << ' ';
dout(T...);
}
//mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
typedef pair <int, int> pii;
const int N = 1000003, M = 1000000;
int n, a[N], fen[N];
void upd(int x) {
for (; x <= M; x |= (x + 1)) {
fen[x]++;
}
}
int get(int x) {
int res = 0;
for (; x >= 0; x = (x & (x + 1)) - 1) {
res += fen[x];
}
return res;
}
void solve(int tc) {
// check for (int i = 0; i < n; j++)
cin >> n;
for (int i = 1; i <= n; i++) {
cin >> a[i];
}
int j = 1, ans = 0, i = 1;
while (i <= n) {
while (j <= n && ((a[j] >= a[j - 1] && get(a[j] - 1) - get(a[i]) <= 0) || j == i)) {
j++;
}
for (int k = i; k < j; k++) {
upd(a[k]);
}
ans++;
i = j;
}
cout << ans;
}
signed main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
// freopen("input.txt", "r", stdin);
// freopen("output.txt", "w", stdout);
int tc = 1;
// cin >> tc;
for (int i = 0; i < tc; i++) {
solve(i);
// cleanup();
}
}
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