oj.uz

답안 #171801

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
171801 2019-12-30T12:24:12 Z davitmarg K개의 묶음 (IZhO14_blocks) C++17
53 / 100
 1000 ms 117112 KB 
/*DavitMarg*/
#include <iostream>
#include <algorithm>
#include <cmath>
#include <vector>
#include <string>
#include <cstring>
#include <map>
#include <unordered_map>
#include <set>
#include <queue>
#include <iomanip>
#include <bitset>
#include <stack>
#include <cassert>
#include <iterator>
#include <fstream>
#define mod 1000000007ll
#define LL long long
#define LD long double
#define MP make_pair
#define PB push_back
#define all(v) v.begin(), v.end()
using namespace std;

char readchar()
{
    char c = getchar();
    while (c <= 33)
    {
        c = getchar();
    }
    return c;
}

int readint()
{
    char c = getchar();
    while (c <= 33)
    {
        c = getchar();
    }
    bool sign = false;
    if (c == '-')
    {
        sign = true;
        c = getchar();
    }
    int t = 0;
    while (c >= '0' && c <= '9')
    {
        t = (t << 3) + (t << 1) + c - '0';
        c = getchar();
    }
    return (sign ? -t : t);
}

const int N = 100005;

int n, k;
LL a[N], lst[N], dp[N][105];
LL t[105][4 * N];

void build(int k, int v, int l, int r)
{
    t[k][v] = mod * mod;
    if (l != r)
    {
        int m = (l + r) / 2;
        build(k, v * 2, l, m);
        build(k, v * 2 + 1, m + 1, r);
    }
}

void upd(int k, int v, int l, int r, int pos, LL val)
{
    if (l == r)
    {
        t[k][v] = min(val, t[k][v]);
        return;
    }
    int m = (l + r) / 2;
    if (pos <= m)
        upd(k, v * 2, l, m, pos, val);
    else
        upd(k, v * 2 + 1, m + 1, r, pos, val);
    t[k][v] = min(t[k][v * 2], t[k][v * 2 + 1]);
}

LL get(int k, int v, int l, int r, int i, int j)
{
    if (i > j)
        return mod * mod;
    if (l == i && r == j)
        return t[k][v];
    int m = (l + r) / 2;
    return min(
        get(k, v * 2, l, m, i, min(j, m)),
        get(k, v * 2 + 1, m + 1, r, max(i, m + 1), j));
}

vector<int> s;
int main()
{
    cin >> n >> k;
    for (int i = 1; i <= n; i++)
        a[i] = readint();

    a[0] = mod;
    s.PB(0);
    for (int i = 1; i <= n; i++)
    {
        while (a[s.back()] <= a[i])
            s.pop_back();
        lst[i] = s.back();
        s.PB(i);
    }
    for (int i = 0; i <= n; i++)
        for (int j = 0; j <= k; j++)
            dp[i][j] = mod * mod;
    for (int j = 0; j <= k; j++)
        build(j, 1, 0, n);
    dp[0][0] = 0;
    upd(0, 1, 0, n, 0, 0);
    for (int i = 1; i <= n; i++)
        for (int j = 1; j <= k; j++)
        {
            dp[i][j] = min(dp[i][j], dp[lst[i]][j]);
            // for (int x = i; x > lst[i]; x--)
            //     dp[i][j] = min(dp[i][j], dp[x - 1][j - 1] + a[i]);
            dp[i][j] = min(dp[i][j], get(j - 1, 1, 0, n, lst[i], i - 1) + a[i]);
            upd(j, 1, 0, n, i, dp[i][j]);
        }
    cout << dp[n][k] << endl;
    return 0;
}

/*

2 4
9 10
5 4 5 5


*/

Subtask #1
14.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 376 KB Output is correct
2 Correct 2 ms 376 KB Output is correct
3 Correct 2 ms 376 KB Output is correct
4 Correct 2 ms 376 KB Output is correct
5 Correct 2 ms 376 KB Output is correct
6 Correct 2 ms 376 KB Output is correct
7 Correct 2 ms 376 KB Output is correct
8 Correct 2 ms 376 KB Output is correct
9 Correct 2 ms 376 KB Output is correct
10 Correct 2 ms 380 KB Output is correct
11 Correct 2 ms 376 KB Output is correct
12 Correct 2 ms 376 KB Output is correct
13 Correct 2 ms 504 KB Output is correct
14 Correct 2 ms 504 KB Output is correct
15 Correct 2 ms 380 KB Output is correct
16 Correct 2 ms 376 KB Output is correct
17 Correct 2 ms 376 KB Output is correct
18 Correct 2 ms 504 KB Output is correct

Subtask #2
18.0 / 18.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 376 KB Output is correct
2 Correct 2 ms 376 KB Output is correct
3 Correct 2 ms 376 KB Output is correct
4 Correct 2 ms 376 KB Output is correct
5 Correct 2 ms 376 KB Output is correct
6 Correct 2 ms 376 KB Output is correct
7 Correct 2 ms 376 KB Output is correct
8 Correct 2 ms 376 KB Output is correct
9 Correct 2 ms 376 KB Output is correct
10 Correct 2 ms 376 KB Output is correct
11 Correct 2 ms 376 KB Output is correct
12 Correct 2 ms 376 KB Output is correct
13 Correct 2 ms 364 KB Output is correct
14 Correct 2 ms 524 KB Output is correct
15 Correct 2 ms 508 KB Output is correct
16 Correct 2 ms 504 KB Output is correct
17 Correct 2 ms 504 KB Output is correct
18 Correct 2 ms 376 KB Output is correct
19 Correct 2 ms 504 KB Output is correct
20 Correct 2 ms 504 KB Output is correct

Subtask #3
21.0 / 21.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3 ms 888 KB Output is correct
2 Correct 2 ms 376 KB Output is correct
3 Correct 2 ms 376 KB Output is correct
4 Correct 2 ms 376 KB Output is correct
5 Correct 2 ms 376 KB Output is correct
6 Correct 2 ms 376 KB Output is correct
7 Correct 2 ms 376 KB Output is correct
8 Correct 2 ms 376 KB Output is correct
9 Correct 2 ms 376 KB Output is correct
10 Correct 2 ms 376 KB Output is correct
11 Correct 2 ms 376 KB Output is correct
12 Correct 2 ms 376 KB Output is correct
13 Correct 2 ms 632 KB Output is correct
14 Correct 2 ms 632 KB Output is correct
15 Correct 4 ms 1400 KB Output is correct
16 Correct 4 ms 1400 KB Output is correct
17 Correct 3 ms 1016 KB Output is correct
18 Correct 4 ms 1400 KB Output is correct
19 Correct 4 ms 1400 KB Output is correct

Subtask #4
0 / 47.0

# 결과 실행 시간 메모리 Grader output
1 Correct 73 ms 15608 KB Output is correct
2 Correct 58 ms 39676 KB Output is correct
3 Correct 145 ms 45816 KB Output is correct
4 Execution timed out 1014 ms 117112 KB Time limit exceeded
5 Halted 0 ms 0 KB -