제출 #169126

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
169126		LinusTorvaldsFan	금 캐기 (IZhO14_divide)	C++14	48 / 100	512 ms	262144 KiB

divide

#include <iostream>
#include <algorithm>
#include <vector>

using namespace std;

const int maxn = 100000 + 7;

typedef long long ll;

const ll infll = 1e15;

int x[maxn];
int g[maxn];
int d[maxn];
ll pr_d[maxn];
ll pr_g[maxn];

struct Node {
	ll l, r;
	ll val;
	Node* left;
	Node* right;
	Node(ll val_, ll l_, ll r_) {
		val = val_;
		l = l_;
		r = r_;
		left = nullptr;
		right = nullptr;
	}
};

void pull(Node* root) {
	if (root->left != nullptr) {
		root->val = min(root->val, root->left->val);
	}
	if (root->right != nullptr) {
		root->val = min(root->val, root->right->val);
	}
}

void add(Node* root, ll val, ll ind) {
	if (root->l == ind && root->r == ind + 1) {
		root->val = min(val,root->val);
		return;
	}
	ll m = (root->l + root->r) / 2;
	if (ind < m) {
		if (root->left == nullptr) {
			root->left = new Node(val, root->l, m);
		}
		add(root->left, val, ind);
	}
	else {
		if (root->right == nullptr) {
			root->right = new Node(val, m, root->r);
		}
		add(root->right, val, ind);
	}
	pull(root);
}

ll get(Node* root, ll l, ll r) {
	if (root->l >= r || root->r <= l) {
		return infll;
	}
	if (root->l >= l && root->r <= r) {
		return root->val;
	}
	ll m = (root->l + root->r) / 2;
	if (root->left == nullptr) {
		root->left = new Node(infll, root->l, m);
	}
	if (root->right == nullptr) {
		root->right = new Node(infll, m, root->r);
	}
	return min(get(root->left, l, r), get(root->right, l, r));
}


int main() {
	ios_base::sync_with_stdio(0); cin.tie(0);
	int n;
	cin >> n;
	for (int i = 0; i < n; i++) {
		cin >> x[i] >> g[i] >> d[i];
	}
	vector<pair<ll, ll>> q;
	for (int i = 0; i < n; i++) {
		pr_d[i] = (i>0?pr_d[i-1]:0) + d[i];
		pr_g[i] = (i > 0 ? pr_g[i - 1] : 0) + g[i];
	}
	Node* root = new Node(infll, -infll, infll);
	ll gold = 0;
	for (int i = 0; i < n; i++) {
		ll  val = (i > 0 ? pr_g[i - 1] : 0);
		ll ind = (i > 0 ? pr_d[i - 1] : 0) - x[i];
		q.emplace_back(((i>0?pr_d[i - 1]:0) - x[i]),(i>0?pr_g[i-1]:0));
		add(root, val, ind);
		ll cur = pr_d[i] - x[i];
		/*for (auto t : q) {
			if (cur >= t.first) {
				gold = max(gold, pr_g[i] - t.second);
			}
		}*/
		gold = max(gold, pr_g[i] - get(root, -infll, cur+1));
	}
	cout << gold;
	return 0;
}

• Subtask 1: 17 / 17
• Subtask 2: 31 / 31
• Subtask 3: 0 / 52