제출 #167976

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
167976		thecodingwizard	Dragon 2 (JOI17_dragon2)	C++11	0 / 100	4030 ms	37620 KiB

dragon2

//#pragma GCC optimize ("O3")
//#pragma GCC target ("sse4")

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp> // Common file
#include <ext/pb_ds/tree_policy.hpp> // Including tree_order_statistics_node_update

using namespace std;
using namespace __gnu_pbds;

template<class T> using min_heap = priority_queue<T, vector<T>, greater<T>>;

#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define F0R1(i, a) for (int i=1; i<=(a); i++)
#define FORd(i, a, b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i, a) for (int i = (a)-1; i >= 0; i--)
#define trav(a, x) for (auto& a : x)
#define MIN(a, b) a = min(a, b)
#define MAX(a, b) a = max(a, b)

#define INF 1000000010
#define LL_INF 4500000000000000000LL
#define LSOne(S) (S & (-S))
#define EPS 1e-9
#define pA first
#define pB second
#define mp make_pair
#define mt make_tuple
#define pb push_back
#define eb emplace_back
#define PI acos(-1.0)
// #define MOD (int)(2e+9+11)
#define MOD (int)(1e+9+7)
#define SET(vec, val, size) for (int i = 0; i < size; i++) vec[i] = val;
#define SET2D(arr, val, dim1, dim2) F0R(i, dim1) F0R(j, dim2) arr[i][j] = val;
#define SET3D(arr, val, dim1, dim2, dim3) F0R(i, dim1) F0R(j, dim2) F0R(k, dim3) arr[i][j][k] = val;
#define SET4D(arr, val, dim1, dim2, dim3, dim4) F0R(i, dim1) F0R(j, dim2) F0R(k, dim3) F0R(l, dim4) arr[i][j][k][l] = val;

#define lb lower_bound
#define ub upper_bound
#define sz(x) (int)x.size()
#define beg(x) x.begin()
#define en(x) x.end()
#define all(x) beg(x), en(x)
#define resz resize
#define SORT(vec) sort(all(vec))
#define RSORT(vec) sort(vec.rbegin(),vec.rend())

typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
typedef pair<int, int> ii;
typedef pair<int, ii> iii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<iii> viii;
typedef vector<ll> vl;

// @formatter:off
// Source: Benq (https://github.com/bqi343/USACO) [Modified]
namespace input {
    template<class T> void re(complex<T>& x);
    template<class T1, class T2> void re(pair<T1,T2>& p);
    template<class T> void re(vector<T>& a);
    template<class T, size_t SZ> void re(array<T,SZ>& a);
    template<class T> void reA(T A[], int sz);

    template<class T> void re(T& x) { cin >> x; }
    void re(double& x) { string t; re(t); x = stod(t); }
    void re(ld& x) { string t; re(t); x = stold(t); }
    template<class Arg, class... Args> void re(Arg& first, Args&... rest) {
        re(first); re(rest...);
    }

    template<class T1, class T2> void re(pair<T1,T2>& p) { re(p.pA,p.pB); }
    template<class T> void re(vector<T>& a) { F0R(i,sz(a)) re(a[i]); }
    template<class T, size_t SZ> void re(array<T,SZ>& a) { F0R(i,SZ) re(a[i]); }
    template<class T> void reA(T A[], int sz) { F0R(i, sz) re(A[i]); }

    void setupIO(const string &PROB = "") {
        ios::sync_with_stdio(false);
        cin.tie(nullptr);
        if (PROB.length() != 0) {
            ifstream infile(PROB + ".in");
            if (infile.good()) {
                freopen((PROB + ".in").c_str(), "r", stdin);
                freopen((PROB + ".out").c_str(), "w", stdout);
            }
        }
    }
}
using namespace input;

namespace output {
    template<class T1, class T2> void prD(const pair<T1,T2>& x);
    template<class T, size_t SZ> void prD(const array<T,SZ>& x);
    template<class T> void prD(const vector<T>& x);
    template<class T> void prD(const set<T>& x);
    template<class T1, class T2> void prD(const map<T1,T2>& x);

    template<class T1, class T2> void pr(const pair<T1,T2>& x);
    template<class T, size_t SZ> void pr(const array<T,SZ>& x);
    template<class T> void pr(const vector<T>& x);
    template<class T> void pr(const set<T>& x);
    template<class T1, class T2> void pr(const map<T1,T2>& x);

    template<class T> void prD(const T& x) { cout << x; cout.flush(); }
    template<class Arg, class... Args> void prD(const Arg& first, const Args&... rest) {
        prD(first); prD(rest...);
    }

    template<class T1, class T2> void prD(const pair<T1,T2>& x) {
        prD("{",x.pA,", ",x.pB,"}");
    }
    template<class T> void prDContain(const T& x) {
        prD("{");
        bool fst = 1; for (const auto& a: x) prD(!fst?", ":"",a), fst = 0; // const needed for vector<bool>
        prD("}");
    }
    template<class T, size_t SZ> void prD(const array<T,SZ>& x) { prDContain(x); }
    template<class T> void prD(const vector<T>& x) { prDContain(x); }
    template<class T> void prD(const set<T>& x) { prDContain(x); }
    template<class T1, class T2> void prD(const map<T1,T2>& x) { prDContain(x); }

    void psD() { prD("\n"); }
    template<class Arg> void psD(const Arg& first) {
        prD(first); psD(); // no space at end of line
    }
    template<class Arg, class... Args> void psD(const Arg& first, const Args&... rest) {
        prD(first," "); psD(rest...); // print w/ spaces
    }


    template<class T> void pr(const T& x) { cout << x; }
    template<class Arg, class... Args> void pr(const Arg& first, const Args&... rest) {
        pr(first); pr(rest...);
    }

    template<class T1, class T2> void pr(const pair<T1,T2>& x) {
        pr(x.pA, " ", x.pB);
    }
    template<class T> void prContain(const T& x) {
        bool fst = 1; for (const auto& a: x) pr(!fst?" ":"",a), fst = 0; // const needed for vector<bool>
    }
    template<class T, size_t SZ> void pr(const array<T,SZ>& x) { prContain(x); }
    template<class T> void pr(const vector<T>& x) { prContain(x); }
    template<class T> void pr(const set<T>& x) { prContain(x); }
    template<class T1, class T2> void pr(const map<T1,T2>& x) { prContain(x); }

    void ps() { pr("\n"); }
    template<class Arg> void ps(const Arg& first) {
        pr(first); ps(); // no space at end of line
    }
    template<class Arg, class... Args> void ps(const Arg& first, const Args&... rest) {
        pr(first," "); ps(rest...); // print w/ spaces
    }
}
using namespace output;
// @formatter:on

/* ============================ */

double DEG_to_RAD(double d) { return d*PI / 180.0; }

double RAD_to_DEG(double r) { return r*180.0 / PI; }

struct point { double x, y;   // only used if more precision is needed
    point() { x = y = 0.0; }                      // default constructor
    point(double _x, double _y) : x(_x), y(_y) {}        // user-defined
    bool operator == (point other) const {
        return (fabs(x-other.x) < EPS && (fabs(y-other.y) < EPS)); }
    bool operator <(const point &p) const {
        return x < p.x || (abs(x-p.x) < EPS && y < p.y); } };

struct vec { double x, y;  // name: `vec' is different from STL vector
    vec(double _x, double _y) : x(_x), y(_y) {} };

vec toVec(point a, point b) {       // convert 2 points to vector a->b
    return vec(b.x-a.x, b.y-a.y); }

double dot(vec a, vec b) { return (a.x*b.x + a.y*b.y); }

double norm_sq(vec v) { return v.x*v.x + v.y*v.y; }

double angle(point a, point o, point b) {  // returns angle aob in rad
    vec oa = toVec(o, a), ob = toVec(o, b);
    return acos(dot(oa, ob) / sqrt(norm_sq(oa) * norm_sq(ob))); }

double cross(vec a, vec b) { return a.x*b.y - a.y*b.x; }

// note: to accept collinear points, we have to change the `> 0'
// returns true if point r is on the left side of line pq
bool ccw(point p, point q, point r) {
    return cross(toVec(p, q), toVec(p, r)) > 0; }

int n, m;
pair<point, int> A[30000];
point a, b;
vector<pair<double, int>> sorted;
vector<int> toProcess;
bool isBelow[30000];

typedef tree<
        double,
        null_type,
        less<double>,
        rb_tree_tag,
        tree_order_statistics_node_update>
        ordered_set;

void solve(int t1, int t2) {
    ordered_set lower, upper;

    trav(x, toProcess) {
        if (A[x].pB == t2 && isBelow[x]) {
            lower.insert(angle(a, b, A[x].pA));
        }
    }
    trav(x, toProcess) {
        if (A[x].pB == t1) {
            if (isBelow[x]) {

            } else {

            }
        } else {
            if (isBelow[x]) {
                lower.erase(angle(a, b, A[x].pA));
            } else {
                upper.insert(angle(a, b, A[x].pA));
            }
        }
    }
}

int main() {
    setupIO();

    re(n, m);
    F0R(i, n) {
        int a, b, c; re(a, b, c);
        A[i] = {point(a, b), c-1};
    }
    re(a.x, a.y, b.x, b.y);

    F0R(i, n) {
        if (ccw(b, a, A[i].pA)) {
            isBelow[i] = true;
            sorted.pb({PI-angle(b, a, A[i].pA), i});
        } else {
            isBelow[i] = false;
            sorted.pb({angle(b, a, A[i].pA), i});
        }
    }
    sort(all(sorted));

    int ct[3000][3000]; SET2D(ct, 0, 3000, 3000);
    F0R(i, n) {
        F0R(j, n) {
            if ((isBelow[i] && isBelow[j]) || (!isBelow[i] && !isBelow[j])) {
                if (angle(b, a, A[i].pA) > angle(b, a, A[j].pA) && angle(a, b, A[i].pA) > angle(a, b, A[j].pA)) ct[A[i].pB][A[j].pB]++;
            } else {
                if (angle(b, a, A[i].pA) + angle(b, a, A[j].pA) <= PI/2 && angle(a, b, A[i].pA) + angle(a, b, A[j].pA) <= PI/2) ct[A[i].pB][A[j].pB]++;
            }
        }
    }

    int q; re(q);
    F0R(i, q) {
        int a, b; re(a, b); --a; --b;
        ps(ct[a][b]);

//        toProcess.clear();
//        F0R(i, n) {
//            if (A[i].pB == a || A[i].pB == b) toProcess.pb(i);
//        }
//
//        solve(a, b);
    }

    return 0;
}

컴파일 시 표준 에러 (stderr) 메시지

dragon2.cpp: In function 'void input::setupIO(const string&)':
dragon2.cpp:88:24: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
                 freopen((PROB + ".in").c_str(), "r", stdin);
                 ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
dragon2.cpp:89:24: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
                 freopen((PROB + ".out").c_str(), "w", stdout);
                 ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 0 / 15
• Subtask 2: 0 / 45
• Subtask 3: 0 / 40