제출 #167924

#제출 시각아이디문제언어결과실행 시간메모리
167924achibasadzishvili학교 설립 (IZhO13_school)C++14
15 / 100
172 ms25016 KiB
#include<bits/stdc++.h> #define ll long long #define f first #define s second #define pb push_back using namespace std; ll n,m,s,prea[500005],preb[500005],ans,cur,fix[500005],raod,ind; ll af[500005],bf[500005],pown = 1; pair<ll,ll>t[5000005],a[400005],b[400005]; void upd(ll x){ if(!x)return; t[x].f = t[2 * x].f + t[2 * x + 1].f; t[x].s = t[2 * x].s + t[2 * x + 1].s; upd(x / 2); } void ad(ll x){ ll f = af[x] - bf[x] + 100005; t[pown + f - 1].f = 1; t[pown + f - 1].s = af[x] - bf[x]; upd((pown + f - 1) / 2); } void rem(ll x){ ll f = af[x] - bf[x] + 100005; t[pown + f - 1].f = 0; t[pown + f - 1].s = 0; upd((pown + f - 1) / 2); } void countt(ll x,ll L,ll R){ if(t[x].f <= raod){ raod -= t[x].f; cur += t[x].s; return; } if(L == R)return; if(t[2 * x].f >= raod) countt(2 * x , L , (L + R) / 2); else { cur += t[2 * x].s; countt(2 * x + 1 , (L + R) / 2 + 1 , R); } } int main(){ ios::sync_with_stdio(false); cin >> n >> m >> s; while(pown <= 1000000) pown *= 2; for(int i=1; i<=n; i++){ cin >> a[i].f >> b[i].f; af[i] = a[i].f; bf[i] = b[i].f; a[i].s = b[i].s = i; } sort(a + 1 , a + n + 1); reverse(a + 1 , a + n + 1); sort(b + 1 , b + n + 1); reverse(b + 1 , b + n + 1); for(int i=1; i<=n; i++) prea[i] = prea[i - 1] + a[i].f; for(int i=1; i<=n; i++) preb[i] = preb[i - 1] + b[i].f; for(int i=1; i<=m; i++) fix[a[i].s] = 1; ll saerto = 0 , sumb = 0; for(int i=1; i<=n; i++){ fix[b[i].s]++; if(fix[b[i].s] == 2){ saerto++; if(m + i - saerto > s + m){ saerto--; fix[b[i].s]--; break; } ad(b[i].s); } if(m + i - saerto > s + m){fix[b[i].s]--;break;} if(m + i - saerto <= s + m)ind = i; } for(int i=1; i<=ind; i++) if(fix[b[i].s] == 1) sumb += b[i].f; for(int i=m; i<=n; i++){ if(i > m){ fix[a[i].s]++; if(fix[a[i].s] == 2){ saerto++; sumb -= bf[a[i].s]; ad(a[i].s); } } while(i + ind - saerto > s + m){ fix[b[ind].s]--; if(fix[b[ind].s] == 1){ rem(b[ind].s); saerto--; } else { sumb -= b[ind].f; } ind--; if(ind < s)break; } if(ind < s)break; raod = i - m; cur = 0; countt(1 , 1 , pown); ans = max(ans , prea[i] + sumb - cur); } cout << ans << endl; return 0; }
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