제출 #167104

#제출 시각아이디문제언어결과실행 시간메모리
167104wleung_bvg모임들 (IOI18_meetings)C++14
19 / 100
5581 ms30180 KiB
#include "meetings.h" #include <bits/stdc++.h> using namespace std; template<class C>constexpr int sz(const C&c){return int(c.size());} using ll=long long;constexpr const char nl='\n',sp=' '; template <class T, class F> struct SparseTable { int N, lg; vector<vector<T>> ST; F op; void build() { for (int i = 0; i < lg - 1; i++) for (int j = 0; j < N; j++) ST[i + 1][j] = op(ST[i][j], ST[i][min(j + (1 << i), N - 1)]); } template <class It> SparseTable(It st, It en, F op) : N(en - st), lg(32 - __builtin_clz(N)), ST(lg, vector<T>(st, en)), op(op) { build(); } template <class It> SparseTable(It st, It en) : SparseTable(st, en, F()) {} // 0-indexed, inclusive T query(int l, int r) { int i = 31 - __builtin_clz(r - l + 1); return op(ST[i][l], ST[i][r - (1 << i) + 1]); } }; template <class It, class F> auto makeSparseTable(It st, It en, F op) { return SparseTable<typename std::iterator_traits<It>::value_type, F>(st, en, op); } struct Line { ll m, b; int l, r; Line(ll m, ll b, int l, int r) : m(m), b(b), l(l), r(r) {} }; const ll INF = 0x3f3f3f3f3f3f3f3f; vector<ll> minimum_costs(vector<int> H, vector<int> L, vector<int> R) { int N = sz(H),Q = sz(L); vector<int> P(N, 0); iota(P.begin(), P.end(), 0); auto ST = makeSparseTable(P.begin(), P.end(), [&] (const int &i, const int &j) { return H[i] > H[j] ? i : j; }); vector<ll> ans(Q, INF); vector<vector<int>> queries(N); for (int i = 0; i < Q; i++) { if (L[i] == R[i]) ans[i] = H[L[i]]; else queries[ST.query(L[i], R[i])].push_back(i); } vector<Line> lLines(N, Line(0, INF, N, -1)), rLines(N, Line(0, INF, N, -1)); auto query = [&] (const vector<Line> &lines, ll x) { ll mn = INF; for (auto &&line : lines) if (line.l <= x && x <= line.r) mn = min(mn, line.m * x + line.b); return mn; }; function<void(int, int)> solve = [&] (int l, int r) { if (l > r) return; int m = ST.query(l, r); ll hm = H[m]; solve(l, m - 1); solve(m + 1, r); for (int i : queries[m]) ans[i] = min(query(lLines, L[i]) + (R[i] - m + 1) * hm, query(rLines, R[i]) + (m - L[i] + 1) * hm); ll lDelta = (r - m + 1) * hm, rDelta = (m - l + 1) * hm; for (int i = l; i <= m - 1; i++) lLines[i].b += lDelta; for (int i = m + 1; i <= r; i++) rLines[i].b += rDelta; lLines[m] = Line(-hm, (m < r ? query(lLines, m + 1) : 0) + (m + 1) * hm, l, m); rLines[m] = Line(hm, (l < m ? query(rLines, m - 1) : 0) - (m - 1) * hm, m, r); }; solve(0, N - 1); return ans; }
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