제출 #166187

#제출 시각아이디문제언어결과실행 시간메모리
166187Eae02Global Warming (CEOI18_glo)C++14
100 / 100
399 ms14940 KiB
#include <bits/stdc++.h> #define all(d) begin(d), end(d) using namespace std; using ll = long long; struct SegTree { using T = ll; T f(T a, T b) { return max(a, b); } static constexpr T UNIT = 0; vector<T> s; ll n; SegTree(ll len) : s(2 * len, UNIT), n(len) {} void set(ll pos, T val) { for (s[pos += n] = val; pos /= 2;) s[pos] = f(s[pos * 2], s[pos * 2 + 1]); } T query(ll lo, ll hi) { // query lo to hi (hi not included) T ra = UNIT, rb = UNIT; for (lo += n, hi += n; lo < hi; lo /= 2, hi /= 2) { if (lo % 2) ra = f(ra, s[lo++]); if (hi % 2) rb = f(s[--hi], rb); } return f(ra, rb); } }; int main() { ll n, d; cin >> n >> d; vector<ll> a(n); for (ll i = 0; i < n; i++) cin >> a[i]; vector<ll> distinctA = a; distinctA.push_back(LLONG_MIN); distinctA.push_back(LLONG_MAX); sort(all(distinctA)); distinctA.erase(unique(all(distinctA)), distinctA.end()); vector<array<ll, 2>> dp(n); ll ans = 0; vector<SegTree> st; st.emplace_back(distinctA.size()); st.emplace_back(distinctA.size()); for (ll i = n - 1; i >= 0; i--) { ll lo1 = upper_bound(all(distinctA), a[i]) - distinctA.begin(); for (ll u = 0; u < 2; u++) dp[i][u] = st[u].query(lo1, distinctA.size()) + 1; ll lo2 = upper_bound(all(distinctA), a[i] - d) - distinctA.begin(); dp[i][1] = max(dp[i][1], st[0].query(lo2, distinctA.size()) + 1); for (ll u = 0; u < 2; u++) st[u].set(lo1 - 1, dp[i][u]); ans = max(ans, dp[i][1]); } cout << ans << "\n"; }
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