제출 #165668

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
165668		egekabas	Cezar (COCI16_cezar)	C++14	20 / 100	2 ms	380 KiB

cezar

#include <bits/stdc++.h>
#define ff first
#define ss second
#define pb push_back
#define mp make_pair
using namespace std;
typedef long long   ll;
typedef unsigned long long   ull;
typedef long double ld;
typedef pair<ll, ll>    pll;
typedef pair<ull, ull>    pull;
typedef pair<ll, ll>  pii;
typedef pair<ld, ld>  pld;
ll n;
string s1[109];
string s2[109];
ll a[109];
vector<ll> g[109];
ll inc[109];
ll vis[109];
vector<int> ans;
pll dif(string t1, string t2){
    for(int i = 0; i < min(t1.size(), t2.size()); ++i)
        if(t1[i] != t2[i]){
            return {t1[i]-'a', t2[i]-'a'};
        }
    if(t2.size() < t1.size()){
        cout << "NE\n";
        exit(0);
    }
    else{
        return {-1, -1};
    }
}
void dfs(ll v){
    vis[v] = 1;
    ans.pb(v);
    for(auto u : g[v]){
        if(vis[u] == 1)
            continue;
        --inc[u];
        if(inc[u] == 0)
            dfs(u);
    }
}
int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    
    //freopen("in.txt", "r", stdin);
    //freopen("out.txt", "w", stdout);

    cin >> n;
    for(int i = 0; i < n; ++i)
        cin >> s1[i];
    for(int i = 0; i < n; ++i){
        cin >> a[i];
        --a[i];
        s2[a[i]] = s1[i];
    }
    for(ll i = 0; i < n-1; ++i){
        pll tmp = dif(s2[i], s2[i+1]);
        if(tmp.ff == -1)
            continue;
        g[tmp.ff].pb(tmp.ss);
        ++inc[tmp.ss];
    }
    for(ll i = 0; i <= 'z'-'a'; ++i){
        if(inc[i] == 0 && vis[i] == 0)
            dfs(i);
    }
    for(ll i = 0; i <= 'z'-'a'; ++i){
        if(vis[i] == 0){
            cout << "NE\n";
            return 0;
        }
    }
    cout << "DA\n";
    for(auto u : ans)
        cout << (char)(u+'a');
}

컴파일 시 표준 에러 (stderr) 메시지

cezar.cpp: In function 'pll dif(std::__cxx11::string, std::__cxx11::string)':
cezar.cpp:23:22: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
     for(int i = 0; i < min(t1.size(), t2.size()); ++i)
                    ~~^~~~~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 0 / 10
• Subtask 2: 0 / 10
• Subtask 3: 10 / 10
• Subtask 4: 0 / 10
• Subtask 5: 0 / 10
• Subtask 6: 10 / 10
• Subtask 7: 0 / 10
• Subtask 8: 0 / 10
• Subtask 9: 0 / 10
• Subtask 10: 0 / 10