Submission #163911

#TimeUsernameProblemLanguageResultExecution timeMemory
163911MvCKangaroo (CEOI16_kangaroo)C++11
51 / 100
2043 ms54136 KiB
//#pragma GCC target("avx2") //#pragma GCC optimization("O3") //#pragma GCC optimization("unroll-loops") #include <bits/stdc++.h> #define rc(x) return cout<<x<<endl,0 #define pb push_back #define mkp make_pair #define in insert #define er erase #define fd find #define fr first #define sc second typedef long long ll; typedef long double ld; const ll INF=0x3f3f3f3f3f3f3f3f; const ll llinf=(1LL<<62); const int inf=(1<<30); const int nmax=2e2+50; const int mod=1e9+7; using namespace std; int n,cs,cf,i,l,r,k,f[nmax][nmax][nmax][2]; void ad(int &x,int y) { x+=y; if(x>=mod)x-=mod; } int main() { //freopen("sol.in","r",stdin); //freopen("sol.out","w",stdout); //mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); ios_base::sync_with_stdio(false);cin.tie(0);cerr.tie(0);cout.tie(0); cin>>n>>cs>>cf; f[1][1][1][0]=f[1][1][1][1]=1; for(i=2;i<=n;i++) { for(l=1;l<i;l++) { for(r=1;r<i;r++) { for(k=1;k<=i;k++) { if(k<=r)ad(f[i][l+(k<=l)][k][1],f[i-1][l][r][0]); else ad(f[i][l+(k<=l)][k][0],f[i-1][l][r][1]); } } } } cout<<(f[n][cs][cf][0]+f[n][cs][cf][1])%mod<<endl; return 0; }
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...