이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//#pragma comment(linker, "/stack:200000000")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
//#pragma GCC optimize("unroll-loops")
#include<bits/stdc++.h>
#include<bits/extc++.h>
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define pb push_back
using namespace std;
using namespace __gnu_pbds;
using ll = long long;
using vi = vector<ll>;
using vvi = vector<vector<ll>>;
const ll mod = 998244353;
using oset = tree<pair<int, int>, null_type, less<pair<int, int>>, rb_tree_tag, tree_order_statistics_node_update>;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int MN = 1e3 + 3;
ll n, a[MN], pref[MN], dp[MN][MN], C[MN][MN], p[MN][MN];
ll f(ll l, ll r, ll i) {
ll a = pref[i] - pref[l - 1];
ll b = pref[r] - pref[i];
return a * b;
}
void bt(int a, int b) {
if(b>n)exit(-1);
cout << b << " ";
if(a>1)
bt(a-1, p[a][b]);
}
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
ll k;
cin >> n >> k;
for (int i = 1; i <= n; i++)
cin >> a[i], pref[i] = pref[i - 1] + a[i];
ll ans = 0, g = n-1;
for(int a = 1; a <= k; a++) {
for(int i = 1; i < n; i++) {
for(int j = 1; j <= i; j++) {
ll t = dp[a-1][j-1] + f(j, n, i);
dp[a][i] = max(dp[a][i], t);
if(dp[a][i]==t)
p[a][i]=j-1;
}
ans = max(ans, dp[a][i]);
if(ans==dp[a][i]) g=i;
}
}
cout << ans << '\n';
bt(k, g);
}
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