Submission #161379

#TimeUsernameProblemLanguageResultExecution timeMemory
161379rama_pangLottery (CEOI18_lot)C++14
100 / 100
1425 ms8376 KiB
#include <bits/stdc++.h> using namespace std; int N, L, q, A[10005]; int ans[105][10005]; int true_ans[105][10005]; pair<int, int> Q[105]; int pos[105]; int main() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> N >> L; for (int i = 0; i < N; i++) cin >> A[i]; cin >> q; for (int i = 0; i < q; i++) cin >> Q[i].first; for (int i = 0; i < q; i++) Q[i].second = i; sort(Q, Q + q); for (int i = 0; i < q; i++) pos[Q[i].second] = i; /* The segment compared is segment i...(i + L - 1) and (i + shift)...(i + L + shift - 1) */ for (int shift = 1, similiar = 0; shift + L - 1 < N; shift++, similiar = 0) { for (int i = 0; i < L; i++) if (A[i] == A[i + shift]) similiar++; for (int i = 0; i + shift + L - 1 < N; i++) { // then sliding window can be used int j = lower_bound(Q, Q + q, make_pair(L - similiar, -1)) - Q; ans[j][i]++, ans[j][i + shift]++; // Add 1 to the answer for the lowest Q possible if (A[i] == A[i + shift]) similiar--; if (A[i + L] == A[i + shift + L]) similiar++; } } /* If Q[i] <= Q[j], then all answers from Q[i] can be used in Q[j] */ for (int i = 0; i < N - L + 1; i++) for (int j = 1; j < q; j++) ans[j][i] += ans[j - 1][i]; for (int i = 0; i < q; i++) { for (int j = 0; j < N - L + 1; j++) cout << ans[pos[i]][j] << " "; cout << "\n"; } }
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