This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "wombats.h"
#include <algorithm>
#include <cstring>
#include <cstdlib>
using namespace std;
struct node{
int adj[205][205];
};
int a[5000][200], b[5000][200];
int n, m;
int opt[205][205];
node merge(node& a, node& b){
node c;
memset(c.adj,0x3f,sizeof(c.adj));
// opt(i-1, j) <= opt(i,j) <= opt(i,j+1)
for(int i=0; i<m; i++){
for(int j=0; j<m; j++){
if(c.adj[0][i] > a.adj[0][j] + b.adj[j][i]){
c.adj[0][i] = a.adj[0][j] + b.adj[j][i];
opt[0][i] = j;
}
}
}
for(int i=1; i<m; i++){
opt[i][m] = m-1;
for(int j=m-1; j>=0; j--){
for(int k=opt[i-1][j]; k<=opt[i][j+1]; k++){
if(c.adj[i][j] > a.adj[i][k] + b.adj[k][j]){
c.adj[i][j] = a.adj[i][k] + b.adj[k][j];
opt[i][j] = k;
}
}
}
}
return c;
}
node tmp[11];
struct seg{
node tree[1050];
void remake(int s, int e, int p){
for(int i=s; i<=e; i++){
for(int j=0; j<m; j++){
for(int k=0; k<m; k++){
tmp[i-s].adj[j][k] = b[i][k] + abs((j ? a[i][j-1] : 0) - (k ? a[i][k-1] : 0));
}
}
}
tree[p] = tmp[0];
for(int i=1; i<=e-s; i++){
tree[p] = merge(tree[p], tmp[i]);
}
}
void add(int pos, int ps, int pe, int p){
if(pe - ps <= 10){
remake(ps, pe, p);
return;
}
int pm = (ps + pe) / 2;
if(pos <= pm) add(pos, ps, pm, 2*p);
else add(pos, pm+1, pe, 2*p+1);
tree[p] = merge(tree[2*p], tree[2*p+1]);
}
void init(int ps, int pe, int p){
if(pe - ps <= 10){
remake(ps, pe, p);
return;
}
int pm = (ps + pe) / 2;
init(ps, pm, 2*p);
init(pm+1, pe, 2*p+1);
tree[p] = merge(tree[2*p], tree[2*p+1]);
}
}seg;
void init(int R, int C, int H[5000][200], int V[5000][200]) {
n = R, m = C;
for(int i=0; i<R; i++){
for(int j=0; j<C; j++){
a[i][j] = H[i][j] + (j ? a[i][j-1] : 0);
b[i][j] = V[i][j];
}
}
seg.init(0,n-1,1);
}
void changeH(int P, int Q, int W) {
int diff = W - (a[P][Q] - (Q ? a[P][Q-1] : 0));
for(int i=Q; i<m; i++){
a[P][i] += diff;
}
seg.add(P,0,n-1,1);
}
void changeV(int P, int Q, int W) {
b[P][Q] = W;
seg.add(P,0,n-1,1);
}
int escape(int V1, int V2) {
return seg.tree[1].adj[V1][V2];
}
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