# |
Submission time |
Handle |
Problem |
Language |
Result |
Execution time |
Memory |
15797 |
2015-07-29T10:41:22 Z |
didw |
맛있는 과자 (kriii3_A) |
C++ |
|
0 ms |
1828 KB |
#include <iostream>
#include <cstdio>
#include <cmath>
using namespace std;
double rs, rb;
double solve(double S0, int n, int k) {
if (n == 0)
return log(S0);
// k가 전체 과자 개수보다 크다면 작은 과자조각으로 반환
if (k > (1<<n)) {
return solve(S0*rs, n-1, k/2);
}
// 아니면 큰 조각으로 반환
return solve(S0*rb, n-1, k);
}
int main() {
int a, b, n, k;
cin >> a >> b >> n >> k;
if (a > b) swap(a, b);
rs = (double)a*a / (double)(a*a + b*b);
rb = (double)b*b / (double)(a*a + b*b);
double S0 = a*b / 2.0;
printf("%.10f\n", solve(S0, n, k));
}
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Incorrect |
0 ms |
1828 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Halted |
0 ms |
0 KB |
- |