/*
Author: Nguyen Tan Bao
Status:
Idea:
*/
#include <bits/stdc++.h>
#define FI first
#define SE second
#define EPS 1e-9
#define ALL(a) a.begin(),a.end()
#define SZ(a) int((a).size())
#define MS(s, n) memset(s, n, sizeof(s))
#define FOR(i,a,b) for (int i = (a); i <= (b); i++)
#define FORE(i,a,b) for (int i = (a); i >= (b); i--)
#define FORALL(it, a) for (__typeof((a).begin()) it = (a).begin(); it != (a).end(); it++)
#define WHATIS(x) cout << #x << " is " << x << endl;
#define ERROR(args...) { string _s = #args; replace(_s.begin(), _s.end(), ',', ' '); stringstream _ss(_s); istream_iterator<string> _it(_ss); err(_it, args); }
//__builtin_ffs(x) return 1 + index of least significant 1-bit of x
//__builtin_clz(x) return number of leading zeros of x
//__builtin_ctz(x) return number of trailing zeros of x
using namespace std;
using ll = long long;
using ld = double;
typedef pair<int, int> II;
typedef pair<II, int> III;
typedef complex<ld> cd;
typedef vector<cd> vcd;
void err(istream_iterator<string> it) {}
template<typename T, typename... Args>
void err(istream_iterator<string> it, T a, Args... args) {
cout << *it << " = " << a << endl;
err(++it, args...);
}
const ll MODBASE = 1000000007LL;
const int MAXN = 10010;
const int MAXM = 1010;
const int MAXK = 110;
const int MAXQ = 200010;
int n, k, leftChild[MAXN], sibling[MAXN], num[MAXN], num2[MAXN];
int dp[MAXN][MAXN][2];
II par[MAXN];
vector<II> a[MAXN];
// reconstruct the tree
void dfs(int u, int p) {
num[u] = 1;
int pre = -1;
FOR(i,0,SZ(a[u])-1) {
int v = a[u][i].FI;
int c = a[u][i].SE;
if (v != p) {
if (pre == -1) leftChild[u] = v;
else sibling[pre] = v;
pre = v;
par[v] = II(u, c);
dfs(v, u);
num[u] += num[v];
}
}
}
void dfs2(int u) {
num2[u] = 1;
if (leftChild[u] != -1) {
dfs2(leftChild[u]);
num2[u] += num2[leftChild[u]];
}
if (sibling[u] != -1) {
dfs2(sibling[u]);
num2[u] += num2[sibling[u]];
}
dp[u][0][0] = dp[u][0][1] = 0;
FOR(i,1,num2[u]) dp[u][i][0] = dp[u][i][1] = -1;
}
int solve(int u, int K, int p) {
if (num2[u] < K) return 1000000000;
if (dp[u][K][p] != -1) return dp[u][K][p];
int res = 1000000000;
int l = leftChild[u], s = sibling[u];
int e = par[u].SE;
if (l == -1 && s == -1) {
if (p == 0) res = 2 * e;
else res = e;
}
if (l != -1 && s == -1) {
if (p == 0) res = min(res, solve(l, K-1, 0) + 2 * e);
else res = min(res, solve(l, K-1, 1) + e);
}
if (l == -1 && s != -1) {
if (p == 0) res = min(res, min(solve(s, K, 0), solve(s, K-1, 0) + 2 * e));
else res = min(res, min(solve(s, K, 1), min(solve(s, K-1, 0) + e, solve(s, K-1, 1) + 2*e)));
}
if (l != -1 && s != -1) {
int L = max(0, K-1-num2[s]), R = min(K-1, num2[l]);
if (p == 0) {
res = min(res, solve(s, K, 0));
FOR(i,L,R) res = min(res, solve(l, i, 0) + solve(s, K-i-1, 0) + 2*e);
}
else {
res = min(res, solve(s, K, 1));
FOR(i,L,R) {
res = min(res, solve(l, i, 1) + solve(s, K-i-1, 0) + e);
res = min(res, solve(l, i, 0) + solve(s, K-i-1, 1) + 2*e);
}
}
}
return dp[u][K][p] = res;
}
int main() {
ios::sync_with_stdio(0);
cin.tie(nullptr);
int x;
cin >> n >> k >> x;
FOR(i,1,n) leftChild[i] = sibling[i] = -1;
FOR(i,1,n-1) {
int u, v, c;
cin >> u >> v >> c;
a[u].emplace_back(II(v, c));
a[v].emplace_back(II(u, c));
}
dfs(x, 0);
dfs2(x);
cout << solve(x, k, 1);
return 0;
}
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
2 ms |
632 KB |
Output is correct |
2 |
Correct |
2 ms |
632 KB |
Output is correct |
3 |
Correct |
2 ms |
632 KB |
Output is correct |
4 |
Correct |
3 ms |
760 KB |
Output is correct |
5 |
Correct |
2 ms |
632 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
67 ms |
45132 KB |
Output is correct |
2 |
Correct |
66 ms |
45460 KB |
Output is correct |
3 |
Correct |
192 ms |
213972 KB |
Output is correct |
4 |
Correct |
92 ms |
97412 KB |
Output is correct |
5 |
Correct |
57 ms |
56252 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
67 ms |
45132 KB |
Output is correct |
2 |
Correct |
66 ms |
45460 KB |
Output is correct |
3 |
Correct |
192 ms |
213972 KB |
Output is correct |
4 |
Correct |
92 ms |
97412 KB |
Output is correct |
5 |
Correct |
57 ms |
56252 KB |
Output is correct |
6 |
Correct |
70 ms |
45852 KB |
Output is correct |
7 |
Correct |
132 ms |
147432 KB |
Output is correct |
8 |
Correct |
497 ms |
433308 KB |
Output is correct |
9 |
Correct |
279 ms |
198648 KB |
Output is correct |
10 |
Correct |
132 ms |
85408 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
2 ms |
632 KB |
Output is correct |
2 |
Correct |
2 ms |
632 KB |
Output is correct |
3 |
Correct |
2 ms |
632 KB |
Output is correct |
4 |
Correct |
3 ms |
760 KB |
Output is correct |
5 |
Correct |
2 ms |
632 KB |
Output is correct |
6 |
Correct |
67 ms |
45132 KB |
Output is correct |
7 |
Correct |
66 ms |
45460 KB |
Output is correct |
8 |
Correct |
192 ms |
213972 KB |
Output is correct |
9 |
Correct |
92 ms |
97412 KB |
Output is correct |
10 |
Correct |
57 ms |
56252 KB |
Output is correct |
11 |
Correct |
70 ms |
45852 KB |
Output is correct |
12 |
Correct |
132 ms |
147432 KB |
Output is correct |
13 |
Correct |
497 ms |
433308 KB |
Output is correct |
14 |
Correct |
279 ms |
198648 KB |
Output is correct |
15 |
Correct |
132 ms |
85408 KB |
Output is correct |
16 |
Correct |
208 ms |
46248 KB |
Output is correct |
17 |
Correct |
476 ms |
45816 KB |
Output is correct |
18 |
Correct |
270 ms |
110328 KB |
Output is correct |
19 |
Correct |
1384 ms |
346788 KB |
Output is correct |
20 |
Correct |
254 ms |
61688 KB |
Output is correct |
21 |
Correct |
775 ms |
138856 KB |
Output is correct |
22 |
Correct |
223 ms |
45816 KB |
Output is correct |
23 |
Correct |
1000 ms |
347836 KB |
Output is correct |
24 |
Correct |
277 ms |
57464 KB |
Output is correct |
25 |
Correct |
1094 ms |
213752 KB |
Output is correct |