Submission #155889

#	Time	Username	Problem	Language	Result	Execution time	Memory
155889		popovicirobert	Coin Collecting (JOI19_ho_t4)	C++14	0 / 100	2 ms	380 KiB

joi2019_ho_t4

#include <bits/stdc++.h>
#define lsb(x) (x & (-x))
#define ll long long
#define ull unsigned long long



#if 0
const int MOD = ;

inline int lgput(int a, int b) {
    int ans = 1;
    while(b > 0) {
        if(b & 1) ans = (1LL * ans * a) % MOD;
        b >>= 1;
        a = (1LL * a * a) % MOD;
    }
    return ans;
}

inline void mod(int &x) {
    if(x >= MOD)
        x -= MOD;
}

inline void add(int &x, int y) {
    x += y;
    mod(x);
}

inline void sub(int &x, int y) {
    x += MOD - y;
    mod(x);
}

inline void mul(int &x, int y) {
    x = (1LL * x * y) % MOD;
}

inline int inv(int x) {
    return lgput(x, MOD - 2);
}
#endif

#if 0
int fact[], invfact[];

inline void prec(int n) {
    fact[0] = 1;
    for(int i = 1; i <= n; i++) {
        fact[i] = (1LL * fact[i - 1] * i) % MOD;
    }
    invfact[n] = lgput(fact[n], MOD - 2);
    for(int i = n - 1; i >= 0; i--) {
        invfact[i] = (1LL * invfact[i + 1] * (i + 1)) % MOD;
    }
}

inline int comb(int n, int k) {
    if(n < k) return 0;
    return (1LL * fact[n] * (1LL * invfact[k] * invfact[n - k] % MOD)) % MOD;
}
#endif

using namespace std;

#define x first
#define y second

const ll INF = 1e18;

int main() {
#ifdef HOME
    ifstream cin("A.in");
    ofstream cout("A.out");
#endif
    int i, n;
    ios::sync_with_stdio(false);
    cin.tie(0), cout.tie(0);

    cin >> n;

    vector < pair <int, int> > pts(2 * n);
    for(i = 0; i < 2 * n; i++) {
        cin >> pts[i].x >> pts[i].y;
    }

    sort(pts.begin(), pts.end());

    auto get = [&](pair <int, int> a, pair <int, int> b) {
        return 1LL * llabs(a.first - b.first) + 1LL * llabs(a.second - b.second);
    };

    vector < vector <ll> > dp(n + 1, vector <ll>(4, INF));
    dp[0][3] = 0;

    int p = 1;
    for(i = 0; i < 2 * n; i++) {
        if(i % 2 == 0) {
            dp[p][1] = dp[p - 1][3] + get(pts[i], {p, 1});
            dp[p][2] = dp[p - 1][3] + get(pts[i], {p, 2});
        }
        else {
            dp[p][3] = min(dp[p][1] + get(pts[i], {p, 2}), dp[p][2] + get(pts[i], {p, 1}));
            p++;
        }
    }

    cout << dp[n][3];

    return 0;
}

• Subtask 1: 0 / 8
• Subtask 2: 0 / 29
• Subtask 3: 0 / 63