제출 #15419

#제출 시각아이디문제언어결과실행 시간메모리
15419myungwoo로봇 심판의 님 게임 (kriii3_F)C++14
0 / 79
2000 ms1724 KiB
#include <bits/stdc++.h> using namespace std; #define pb push_back typedef long long lld; int N, M, K; lld A[21], G[21]; vector <lld> P, Q; lld gcd(lld a, lld b){ return b ? gcd(b, a%b) : a; } inline lld invalid(lld n) { lld ret = n; for (int msk1=0;msk1<(1<<N);msk1++){ int sign = -1; lld lcm = 1; bool none = 0; for (int i=0;i<N;i++) if (msk1 & (1 << i)){ sign *= -1; lld g = gcd(lcm, P[i]); if (P[i] / g > n / lcm){ none = 1; break; } lcm = P[i] / g * lcm; } if (none) continue; if (msk1) ret += sign * n / lcm; // if (msk1) printf("|A| += %lld\n", sign * n / lcm); for (int msk2=0;msk2<(1<<M);msk2++){ int sign2 = sign; lld lcm2 = lcm; bool over = 0; for (int i=0;i<M;i++) if (msk2 & (1 << i)){ sign2 *= -1; lld g = gcd(lcm2, Q[i]); if (Q[i] / g > n / lcm2){ over = 1; break; } lcm2 = Q[i] / g * lcm2; } if (over) continue; if (msk1 + msk2) ret -= (lld)sign2 * n / lcm2; // if (msk1 + msk2) printf("|A or B| += %lld (%d %d)\n", sign2 * n / lcm2, msk1, msk2); } } return ret; } inline lld get_grundy(lld n) { if (!n) return 0; lld me = invalid(n), you = invalid(n-1); return me > you ? 0 : (n - me); } inline lld get_number_with_grundy(lld g, lld n) { lld s = 1, e = n - 1, ret = 0; while (s <= e){ lld m = (s+e) >> 1; if (m - invalid(m) >= g) e = m-1, ret = m; else s = m+1; } return ret; } inline lld get_number_robot_delete(lld n) { lld s = 0, e = n - 2, ret = n - 1; lld v = invalid(n - 1); while (s <= e){ lld m = (s+e) >> 1; if (invalid(m) >= v) e = m-1, ret = m; else s = m+1; } return ret; } int main() { scanf("%d%d%d", &N, &M, &K); for (int i=0;i<N;i++){ lld x; scanf("%lld", &x); P.pb(x); } for (int i=0;i<M;i++){ lld x; scanf("%lld", &x); Q.pb(x); } for (int i=1;i<=K;i++) scanf("%lld", A+i); lld x = 0; for (int i=1;i<=K;i++){ G[i] = get_grundy(A[i]); x ^= G[i]; } // for (int i=1;i<10;i++) printf("%d: %lld\n", i, get_grundy(i)); for (int i=1;i<=K;i++){ if (!G[i]){ puts("0 0"); continue; } lld ox = x ^ G[i]; lld p, q; if (ox){ if (ox < G[i]) p = 1, q = A[i] - get_number_with_grundy(ox, A[i]); else p = q = 0; }else{ p = A[i] - G[i] + 1; q = A[i] - get_number_robot_delete(A[i]); } printf("%lld %lld\n", p, q); } }
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...