이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "museum.h"
#include <set>
#include <bitset>
#include <list>
#include <map>
#include <queue>
#include <stack>
#include <cassert>
#include <cmath>
#include <cstdio>
#include <cstdlib>
#include <iostream>
#include <climits>
#include <cstring>
#include <ctime>
#include <string>
#include <algorithm>
#include <vector>
#include <stack>
#include <sstream>
#define MID(x,y) ( ( x + y ) >> 1 )
#define L(x) ( x << 1 )
#define R(x) ( x << 1 | 1 )
#define REP(i,t) for(int i=0; i<(t); i++)
#define FOR(i,s,t) for(int i=(s); i<(t); i++)
#define FORD(i,a,b) for (int i = (a); i >= (b); i--)
#define FORL(i,s,t) for(L i=(s); i<(t); i++)
#define BUG puts("here!!!")
#define STOP system("pause")
#define file_r(x) freopen(x, "r", stdin)
#define file_w(x) freopen(x, "w", stdout)
#define EPS 1e-11
#define EQ(a, b) (fabs((a) - (b)) <= EPS)
#define POS(a) ((a) >= EPS)
#define NEG(a) ((a) <= -EPS)
#define BG(a, b) ((a) - (b) >= EPS)
#define LS(a, b) ((b) - (a) >= EPS)
#define CLR(a, x) memset( a, x, sizeof( a ) )
#define PI (atan(1.0) * 4)
#define SQ(x) ((x) * (x))
#define DIST(x1, y1, x2, y2) (sqrt(SQ((x1) - (x2)) + SQ((y1) - (y2))))
#define mp(x, y) make_pair(x, y)
#define pb(x) push_back(x)
#define setmin(a, b) (a = min(a, b))
#define setmax(a, b) (a = max(a, b))
#define LOG2(x) (log(x) / log(2))
#define XX first.first
#define XY first.second
#define YX second.first
#define YY second.second
using namespace std;
typedef unsigned long long ULL;
typedef long long LL;
typedef pair<double, double> Pd;
typedef pair<int, int> Pi;
typedef pair<LL, LL> Pl;
LL countSimilarPairs(const std::vector<int> &v) {
int len = v.size();
map<int, int> m;
for (int i = 0; i < len; ++i) {
auto itr = m.find(v[i]);
if (itr == m.end()) {
m[v[i]] = 1;
} else {
itr->second++;
}
}
LL ans = 0;
for (auto e : m) {
if (e.second > 1) {
ans += (e.second + e.second - 1) / 2;
}
}
return ans;
}
long long CountSimilarPairs(std::vector<int> B, std::vector<int> T, std::vector<int> G) {
int len = B.size();
LL ans = countSimilarPairs(B) + countSimilarPairs(T) + countSimilarPairs(G);
vector<int> v;
v.reserve(len);
for (int i = 0; i < len; ++i) {
v[i] = B[i] * 100 + T[i];
}
ans -= countSimilarPairs(v);
for (int i = 0; i < len; ++i) {
v[i] = B[i] * 100 + G[i];
}
ans -= countSimilarPairs(v);
for (int i = 0; i < len; ++i) {
v[i] = G[i] * 100 + T[i];
}
ans -= countSimilarPairs(v);
for (int i = 0; i < len; ++i) {
v[i] = B[i] * 10000 + T[i] * 100 + G[i];
}
ans += countSimilarPairs(v);
return ans;
}
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