제출 #148140

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
148140		abacaba	보물 찾기 (CEOI13_treasure2)	C++14	50 / 100	2 ms	504 KiB

treasure

#include <iostream>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <stdio.h>
#include "treasure.h"
#include <assert.h>
#include <string.h>
using namespace __gnu_pbds;
#include <stdio.h>
#include <algorithm>
#include <math.h>
#include <random>
#include <string>
#include <cstring>
#include <set>
#include <map>
#include <time.h>
using namespace std;

typedef tree <int, null_type, less <int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;

#define max3(a, b, c) max(a, max(b, c))
#define min3(a, b, c) min(a, min(b, c))
#define mp make_pair
#define f first
#define se second
#define pb push_back
#define ppb pop_back
#define ll long long
#define ull unsigned long long
#define cntbit(x) __builtin_popcount(x)
#define endl '\n'
#define uset unordered_set
#define umap unordered_map
#define pii pair<int, int>
#define ld long double
#define pll pair<long long, long long>

int dp[105][105], m, n;

inline pii part(int i, int j) {
	return mp((i - 1) / n, (j - 1) / n);
}

void findTreasure(int N) {
	m = N, n = (N >> 1);
    for(int i = m; i; --i)
    	for(int j = m; j; --j) {
    		if(part(i, j) == mp(1, 1))
    			dp[i][j] = countTreasure(1, 1, i, j);
    		else if(part(i, j) == mp(1, 0))
    			dp[i][j] = dp[i][m] - countTreasure(1, j + 1, i, m);
    		else if(part(i, j) == mp(0, 1))
    			dp[i][j] = dp[m][j] - countTreasure(i + 1, 1, m, j);
    		else
    			dp[i][j] = -(dp[m][m] - dp[i][m] - dp[m][j] - countTreasure(i + 1, j + 1, m, m));
    	}
    for(int i = 1; i <= N; ++i)
    	for(int j = 1; j <= N; ++j)
    		if(dp[i][j] - dp[i-1][j] - dp[i][j-1] + dp[i-1][j-1])
	    		Report(i, j);
}

• Subtask 1: 50 / 100