Submission #147126

#	Time	Username	Problem	Language	Result	Execution time	Memory
147126		abacaba	Paint By Numbers (IOI16_paint)	C++14	59 / 100	44 ms	26104 KiB

paint

#include <iostream>
#include <string>
#include <cstring>
#include <vector>
#include <map>
#include <set>
#include <algorithm>
#include <math.h>
#include <cstdio>
#include <stdio.h>
#include <queue>
#include <cstdlib>
#include <deque>
#include <cassert>
#include "paint.h"
using namespace std;
 
#define max3(a, b, c) max(a, max(b, c))
#define min3(a, b, c) min(a, min(b, c))
#define mp make_pair
#define f first
#define se second
#define pb push_back
#define ppb pop_back
#define ll long long
#define ull unsigned long long
#define cntbit(x) __builtin_popcount(x)
#define endl '\n'
#define uset unordered_set
#define umap unordered_map
#define pii pair<int, int>
#define ld long double
#define pll pair<long long, long long>
 
const int N = 5e5 + 5;
const int K = 1e2 + 5;
int n, k, p[2][N], a[K], pref[2][N];
bool dp[2][K][N];

string solve_puzzle(string s, vector<int> c) {
	string ans = "";
	n = s.size(); k = c.size();
	s = '#' + s + '#';

	for(int i = 0; i < k; ++i)
		a[i+1] = c[i];

	for(int i = 1; i <= n; ++i)
		p[0][i] = p[0][i-1] + (s[i] == '_'),
		p[1][i] = p[1][i-1] + (s[i] == 'X');

	dp[0][0][0] = dp[1][0][0] = true;

	for(int i = 0; i <= k; ++i) {
		for(int j = 1; j <= n; ++j) {
			if(s[j] != '_') {
				if(i > 0 && j >= a[i] && p[0][j] == p[0][j - a[i]] && s[j - a[i]] != 'X')
					dp[0][i][j] |= dp[0][i-1][max(0, j - a[i] - 1)];
			}
			if(s[j] != 'X')
				dp[0][i][j] |= dp[0][i][j-1];
		}
	}

	reverse(a + 1, a + 1 + k);
	reverse(s.begin(), s.end());

	for(int i = 1; i <= n; ++i)
		p[0][i] = p[0][i-1] + (s[i] == '_'),
		p[1][i] = p[1][i-1] + (s[i] == 'X');

	for(int i = 0; i <= k; ++i) {
		for(int j = 1; j <= n; ++j) {
			if(s[j] != '_') {
				if(i > 0 && j >= a[i] && p[0][j] == p[0][j - a[i]] && s[j - a[i]] != 'X')
					dp[1][i][j] |= dp[1][i-1][max(0, j - a[i] - 1)];
			}
			if(s[j] != 'X')
				dp[1][i][j] |= dp[1][i][j-1];
		}
	}

	for(int j = n + 1; j <= n + 3; ++j)
		dp[1][0][j] |= dp[1][0][j-1];

	reverse(dp[1], dp[1] + k + 2);
	reverse(a + 1, a + 1 + k);
	reverse(s.begin(), s.end());

	for(int i = 1; i <= n; ++i)
		p[0][i] = p[0][i-1] + (s[i] == '_'),
		p[1][i] = p[1][i-1] + (s[i] == 'X');

	for(int i = 0; i <= k + 1; ++i)
		reverse(dp[1][i], dp[1][i] + n + 2);

	for(int i = 0; i <= k; ++i)
		for(int j = 1; j <= n; ++j)
			if(dp[0][i][j-1] && s[j] != 'X' && dp[1][i+1][j+1])
				++pref[0][j];

	for(int i = 1; i <= k; ++i) {
		for(int j = 1; j + a[i] - 1 <= n; ++j) {
			if(p[0][j + a[i] - 1] == p[0][j-1] && s[j-1] != 'X' && s[j + a[i]] != 'X' && dp[1][i+1][j + a[i] + 1] && dp[0][i-1][max(j-2, 0)]) {
				++pref[1][j];
				--pref[1][j + a[i]];
			}
		}
	}

	for(int i = 1; i <= n; ++i) {
		pref[1][i] += pref[1][i-1];

		if(pref[1][i] && pref[0][i])
			ans += '?';
		else if(pref[1][i])
			ans += 'X';
		else
			ans += '_';
	}
	return ans;
}

• Subtask 1: 7 / 7
• Subtask 2: 3 / 3
• Subtask 3: 22 / 22
• Subtask 4: 27 / 27
• Subtask 5: 0 / 21
• Subtask 6: 0 / 10
• Subtask 7: 0 / 10