#include <iostream>
#include <string>
#include <cstring>
#include <vector>
#include <map>
#include <set>
#include <algorithm>
#include <math.h>
#include <cstdio>
#include <stdio.h>
#include <queue>
#include <cstdlib>
#include <deque>
#include <cassert>
#include "paint.h"
using namespace std;
#define max3(a, b, c) max(a, max(b, c))
#define min3(a, b, c) min(a, min(b, c))
#define mp make_pair
#define f first
#define se second
#define pb push_back
#define ppb pop_back
#define ll long long
#define ull unsigned long long
#define cntbit(x) __builtin_popcount(x)
#define endl '\n'
#define uset unordered_set
#define umap unordered_map
#define pii pair<int, int>
#define ld long double
#define pll pair<long long, long long>
const int N = 2e5 + 15;
const int K = 1e2 + 15;
int n, k, p[2][N], a[K], pref[2][N];
bool used[K][N], dp[K][N];
bool rec(int pos, int block) {
if(used[block][pos])
return dp[block][pos];
if(block == k) {
if(p[1][n] == p[1][pos + a[block] - 1]) {
++pref[0][pos + a[block]];
return dp[block][pos] = true;
}
return dp[block][pos] = false;
}
used[block][pos] = true;
for(int i = pos + a[block] + 1; i + a[block + 1] - 1 <= n; ++i) {
if(p[1][i-1] != p[1][pos + a[block] - 1])
break;
if(p[0][i + a[block+1] - 1] == p[0][i-1] && rec(i, block + 1)) {
++pref[1][pos];
--pref[1][pos + a[block]];
++pref[1][i];
--pref[1][i + a[block + 1]];
++pref[0][pos + a[block]];
--pref[0][i];
dp[block][pos] = true;
}
}
return dp[block][pos];
}
string solve_puzzle(string s, vector<int> c) {
string ans = "";
n = s.size(); k = c.size();
s = '#' + s;
for(int i = 1; i <= n; ++i)
p[0][i] = p[0][i-1] + (s[i] == '_'),
p[1][i] = p[1][i-1] + (s[i] == 'X');
for(int i = 0; i < k; ++i)
a[i+1] = c[i];
for(int i = 1; !p[1][i-1] && i + a[1] - 1 <= n; ++i)
if(p[0][i + a[1] - 1] == p[0][i-1] && rec(i, 1)) {
++pref[0][1];
--pref[0][i];
++pref[1][i];
--pref[1][i + a[1]];
}
for(int i = 1; i <= n; ++i)
for(int j = 0; j < 2; ++j)
pref[j][i] += pref[j][i-1];
for(int i = 1; i <= n; ++i)
pref[0][i] += (s[i] == '_'),
pref[1][i] += (s[i] == 'X');
for(int i = 1; i <= n; ++i) {
if(pref[1][i] && pref[0][i])
ans += '?';
else if(pref[1][i])
ans += 'X';
else
ans += '_';
}
return ans;
}
