제출 #145669

#제출 시각아이디문제언어결과실행 시간메모리
145669Minnakhmetov모임들 (IOI18_meetings)C++14
19 / 100
775 ms234760 KiB
#include "meetings.h" #include <bits/stdc++.h> using namespace std; #define ll long long #define all(aaa) aaa.begin(), aaa.end() const ll INF = 1e18; const int N1 = 5005, N2 = 1e5 + 5; ll lp[N1][N1], rp[N1][N1]; int n, q; vector<ll> slow(vector<int> a, vector<int> L, vector<int> R) { for (int i = 0; i < n; i++) { ll cur = 0; int mx = a[i]; for (int j = i - 1; j >= 0; j--) { mx = max(mx, a[j]); cur += mx; lp[j][i] = cur; } cur = 0; mx = a[i]; for (int j = i + 1; j < n; j++) { mx = max(mx, a[j]); cur += mx; rp[i][j] = cur; } } vector<ll> ans(q); for (int i = 0; i < q; i++) { ll mn = INF; for (int j = L[i]; j <= R[i]; j++) { mn = min(mn, lp[L[i]][j] + rp[j][R[i]] + a[j]); } ans[i] = mn; } return ans; } int t[N2 * 4]; void build(int v, int L, int R, vector<pair<int, int>> &islands) { if (L == R) { t[v] = islands[L].second - islands[L].first + 1; } else { int m = (L + R) >> 1; build(v * 2, L, m, islands); build(v * 2 + 1, m + 1, R, islands); t[v] = max(t[v * 2], t[v * 2 + 1]); } } int que(int l, int r, int v, int L, int R) { if (l > r) return 0; if (l == L && r == R) return t[v]; int m = (L + R) >> 1; return max(que(l, min(m, r), v * 2, L, m), que(max(m + 1, l), r, v * 2 + 1, m + 1, R)); } vector<ll> binary(vector<int> a, vector<int> L, vector<int> R) { vector<pair<int, int>> islands; for (int i = 0, j = 0; i < n; i++) { if (a[i] == 1) { if (i == n - 1 || a[i + 1] != 1) { islands.push_back({ j, i }); } } else { j = i + 1; } } build(1, 0, islands.size() - 1, islands); vector<ll> ans(q, 0); for (int i = 0; i < q; i++) { auto it = lower_bound(all(islands), make_pair(L[i] + 1, -1)); int x, y, mx = 0; x = it - islands.begin(); if (it != islands.begin()) { it--; if (it->second >= L[i]) { if (R[i] <= it->second) { ans[i] = R[i] - L[i] + 1; continue; } mx = max(mx, it->second - L[i] + 1); } } it = lower_bound(all(islands), make_pair(R[i] + 1, -1)); if (it == islands.begin()) continue; it--; y = int(it - islands.begin()); if (it->second >= R[i]) { mx = max(mx, R[i] - it->first + 1); y--; } mx = max(mx, que(x, y, 1, 0, islands.size() - 1)); ans[i] = (R[i] - L[i] + 1) * 2 - mx; } return ans; } std::vector<long long> minimum_costs(std::vector<int> a, std::vector<int> L, std::vector<int> R) { n = a.size(), q = L.size(); if (n < N1 && q < N1) { return slow(a, L, R); } return binary(a, L, R); }
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