이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define fi first
#define se second
#define LINF 1000000000000000000LL
#define eb emplace_back
#define all(v) (v).begin(), (v).end()
 
using namespace std;
typedef long long ll;
typedef pair <ll, ll> pll;
 
int t[101010];
ll b[101010], tree[808080];
ll update(int node, int s, int e, int k, ll val) {
	if(s == e) return tree[node] = max(tree[node], val);
	int m = (s + e) >> 1;
	if(k <= m) return tree[node] = max(tree[node*2+1], update(node*2, s, m, k, val));
	else return tree[node] = max(tree[node*2], update(node*2+1, m+1, e, k, val));
}
 
ll cal(int node, int s, int e, int l, int r) {
	if(s > r || e < l) return -LINF;
	if(s >= l && e <= r) return tree[node];
	int m = (s + e) / 2;
	return max(cal(node*2, s, m, l, r), cal(node*2+1, m+1, e, l, r));
}
 
vector <int> num;
int main() {
	int K, m, d, n;
	ll a;
	cin >> K >> m >> d >> a >> n;
	for(int i = 1; i <= n; i++) {
		cin >> t[i] >> b[i];
		t[i] -= K;
		num.eb(t[i]%d);
	}
	num.eb((m-K)%d);
	sort(all(num));
	num.erase(unique(all(num)), num.end());
	for(int i = 0; i < 808080; i++) {
		tree[i] = -LINF;
	}
	update(1, 0, num.size()-1, 0, 0LL);
	for(int i = 1; i < num.size(); i++) {
		update(1, 0, num.size()-1, i, -a);
	}
	for(int i = 1; i <= n; i++) {
		int k = lower_bound(all(num), t[i]%d) - num.begin();
		ll val = cal(1, 0, num.size()-1, k, num.size()-1) + b[i];
		update(1, 0, num.size()-1, k, val);
		if(k < num.size()-1) update(1, 0, num.size()-1, num.size()-1, val - a);
	}
	int k = lower_bound(all(num), (m-K)%d) - num.begin();
	cout << cal(1, 0, num.size()-1, k, num.size()-1) - a * ((ll)(m - K) / d);
}
컴파일 시 표준 에러 (stderr) 메시지
koala.cpp: In function 'int main()':
koala.cpp:47:19: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
  for(int i = 1; i < num.size(); i++) {
                 ~~^~~~~~~~~~~~
koala.cpp:54:8: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
   if(k < num.size()-1) update(1, 0, num.size()-1, num.size()-1, val - a);
      ~~^~~~~~~~~~~~~~| # | Verdict  | Execution time | Memory | Grader output | 
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