제출 #144493

#제출 시각아이디문제언어결과실행 시간메모리
144493liwiAliens (IOI16_aliens)C++11
100 / 100
379 ms6776 KiB
#include "aliens.h" #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; typedef tree<int, null_type, less<int>, rb_tree_tag,tree_order_statistics_node_update> ordered_set; #define scan(x) do{while((x=getchar())<'0'); for(x-='0'; '0'<=(_=getchar()); x=(x<<3)+(x<<1)+_-'0');}while(0) char _; #define complete_unique(a) a.erase(unique(a.begin(),a.end()),a.end()) #define all(a) a.begin(),a.end() #define println printf("\n"); #define readln(x) getline(cin,x); #define pb push_back #define endl "\n" #define INT_INF 0x3f3f3f3f #define LL_INF 0x3f3f3f3f3f3f3f3f #define MOD 1000000007 #define MOD2 1190492669 #define SEED 131 #define mp make_pair #define fastio cin.tie(0); cin.sync_with_stdio(0); #define MAXN 100005 typedef unsigned long long ull; typedef long long ll; typedef long double ld; typedef unordered_map<int,int> umii; typedef pair<int,int> pii; typedef pair<double,double> pdd; typedef pair<ll,ll> pll; typedef pair<int,pii> triple; typedef int8_t byte; mt19937 g1(time(0)); int randint(int a, int b){return uniform_int_distribution<int>(a, b)(g1);} ll randlong(ll a,ll b){return uniform_int_distribution<long long>(a, b)(g1);} ll gcd(ll a, ll b){return b == 0 ? a : gcd(b, a % b);} ll lcm(ll a, ll b){return a*b/gcd(a,b);} ll fpow(ll b, ll exp, ll mod){if(exp == 0) return 1;ll t = fpow(b,exp/2,mod);if(exp&1) return t*t%mod*b%mod;return t*t%mod;} ll divmod(ll i, ll j, ll mod){i%=mod,j%=mod;return i*fpow(j,mod-2,mod)%mod;} int num_points,len,num_photo,ptr,cnt[MAXN],dq[MAXN],l,r; pii points[MAXN],p[MAXN],lst; ld dp[MAXN]; ll m[MAXN]; inline bool cmp(pii &a, pii &b){ if(a.first == b.first) return a.second>b.second; return a.first<b.first; } inline ld calc(int i, int j){ ld c1 = dp[j]+(ld)(p[i].second-p[j+1].first+1)*(p[i].second-p[j+1].first+1); ld c2 = m[j]*m[j]; return c1-c2; } inline ld inter(int j, int k){ ld m1 = (ld)-2.0*(p[j+1].first-1), b1 = (ld)(p[j+1].first-1)*(p[j+1].first-1)+dp[j]-m[j]*m[j]; ld m2 = (ld)-2.0*(p[k+1].first-1), b2 = (ld)(p[k+1].first-1)*(p[k+1].first-1)+dp[k]-m[k]*m[k]; return (ld)(b2-b1)/(m1-m2); } inline int getGroups(ld c){ l = r = 1, dq[1] = 0; dp[0] = cnt[0] = 0; for(int i=1; i<=ptr; i++){ while(r-l >= 1 && calc(i,dq[l]) >= calc(i,dq[l+1])) l++; dp[i] = calc(i,dq[l])+c; cnt[i] = cnt[dq[l]]+1; while(r-l >= 1 && inter(dq[r-1],i) <= inter(dq[r-1],dq[r])) r--; dq[++r] = i; } return cnt[ptr]; } ll take_photos(int nn, int mm, int kk, vector<int> rows, vector<int> cols){ num_points = nn, len = mm, num_photo = kk, ptr = 0; for(int i=1; i<=num_points; i++){ int a = min(rows[i-1],cols[i-1]); int b = max(rows[i-1],cols[i-1]); points[i] = mp(a,b); } sort(points+1,points+num_points+1,cmp); lst = p[++ptr] = points[1], p[0] = mp(-1,-1); for(int i=2; i<=num_points; i++){ int r = points[i].second; if(r > lst.second){ p[++ptr] = points[i]; lst = points[i]; } } for(int i=1; i<ptr; i++) m[i] = max(0,p[i].second-p[i+1].first+1); memset(dp,0x3f,sizeof dp); ld low = 0, high = 1e12, ans = 0; while(high-low >= 1e-6){ ld mid = (low+high)/2; if(getGroups(mid) <= num_photo){ ans = mid; high = mid-1e-6; }else low = mid+1e-6; } getGroups(ans); ll res = round(dp[ptr]-ans*num_photo); return res; }
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