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답안 #144088

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
144088 2019-08-16T02:14:23 Z liwi Akvizna (COCI19_akvizna) C++11
65 / 130
 1500 ms 28568 KB 
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;
typedef tree<int, null_type, less<int>, rb_tree_tag,tree_order_statistics_node_update> ordered_set;

#define scan(x) do{while((x=getchar())<'0'); for(x-='0'; '0'<=(_=getchar()); x=(x<<3)+(x<<1)+_-'0');}while(0)
char _;
#define complete_unique(a) a.erase(unique(a.begin(),a.end()),a.end())
#define all(a) a.begin(),a.end()
#define println printf("\n");
#define readln(x) getline(cin,x);
#define pb push_back
#define endl "\n"
#define INT_INF 0x3f3f3f3f
#define LL_INF 0x3f3f3f3f3f3f3f3f
#define MOD 1000000007
#define MOD2 1190492669
#define SEED 131
#define mp make_pair
#define fastio cin.tie(0); cin.sync_with_stdio(0);

#define MAXN 100005
#define MAXV 100005

typedef unsigned long long ull;
typedef long long ll;
typedef long double ld;
typedef unordered_map<int,int> umii;
typedef pair<int,int> pii;
typedef pair<double,double> pdd;
typedef pair<ll,ll> pll;
typedef pair<int,pii> triple;
typedef int8_t byte;

mt19937 g1(time(0));

int randint(int a, int b){return uniform_int_distribution<int>(a, b)(g1);}
ll randlong(ll a,ll b){return uniform_int_distribution<long long>(a, b)(g1);}

ll gcd(ll a, ll b){return b == 0 ? a : gcd(b, a % b);}
ll lcm(ll a, ll b){return a*b/gcd(a,b);}
ll fpow(ll  b, ll exp, ll mod){if(exp == 0) return 1;ll t = fpow(b,exp/2,mod);if(exp&1) return t*t%mod*b%mod;return t*t%mod;}
ll divmod(ll i, ll j, ll mod){i%=mod,j%=mod;return i*fpow(j,mod-2,mod)%mod;}

struct node{
	int l,r;
	pair<int,pair<ld,ld>> bst;
};

struct MaxLiChaoTree{
	node seg[4*MAXV];
	inline ld calc(int rt, int m){return seg[rt].bst.second.first*m+seg[rt].bst.second.second;}
	inline ld calc(pair<ld,ld> bst, int m){return bst.first*m+bst.second;}
	inline ld inter(pair<ld,ld> f, pair<ld,ld> s){return (s.second-f.second)/(f.first-s.first);}
	void build(int l, int r, int rt){
		seg[rt].l = l, seg[rt].r = r, seg[rt].bst = mp(-1,mp(0,-LL_INF));
		if(l == r) return;
		int mid = (l+r)/2;
		build(l,mid,rt<<1);
		build(mid+1,r,rt<<1|1);
	}
	void add_line(int rt, pair<int,pair<ld,ld>> line){
		if(seg[rt].l == seg[rt].r){
			if(calc(line.second,seg[rt].l) >= calc(rt,seg[rt].l)) seg[rt].bst = line;
			return;
		}
		int mid = (seg[rt].l+seg[rt].r)/2;
		bool f = calc(rt,seg[rt].l) <= calc(line.second,seg[rt].l);
		bool s = calc(rt,seg[rt].r) <= calc(line.second,seg[rt].r);
		if(f && s){
			seg[rt].bst = line;
			return;
		}else if(!f && !s) return;
		ld x = inter(line.second,seg[rt].bst.second);
		if(x <= mid){
			if(calc(line.second,mid) >= calc(rt,mid)) swap(line,seg[rt].bst);
			add_line(rt<<1,line);
		}else{
			if(calc(line.second,mid) >= calc(rt,mid)) swap(line,seg[rt].bst);
			add_line(rt<<1|1,line);
		}
	}
	pair<ld,int> get(int rt, int pos){
		if(seg[rt].l == seg[rt].r) return mp(calc(rt,pos),seg[rt].bst.first);
		int mid = (seg[rt].l+seg[rt].r)/2;
		if(pos <= mid) return max(mp(calc(rt,pos),seg[rt].bst.first),get(rt<<1,pos));
		return max(mp(calc(rt,pos),seg[rt].bst.first),get(rt<<1|1,pos));
	}
};

int N,K;
//double dp2[MAXN][MAXN];
pair<ld,int> dp[MAXN];
MaxLiChaoTree t;

inline double inter(int j, int k){
	double m1 = dp[j].first, b1 = -j;
	double m2 = dp[k].first, b2 = -k;
	return (b2-b1)/(m1-m2);
}

inline int getGroups(double C){
//	deque<int> dq; dq.pb(0);
	t.build(1,N,1); t.add_line(1,mp(0,mp(0,0)));
	for(int i=1; i<=N; i++){
//		while(dq.size() >= 2 && dp[dq[0]].first*i-dq[0] <= dp[dq[1]].first*i-dq[1]) dq.pop_front();
		pair<ld,int> p = t.get(1,i);
		dp[i].first = p.first/i+1-C;
		dp[i].second = dp[p.second].second+1;
//		while(dq.size() >= 2 && inter(dq[dq.size()-2],i) <= inter(dq[dq.size()-2],dq.back())) dq.pop_back();
//		dq.pb(i);
		t.add_line(1,mp(i,mp(dp[i].first,-i)));
	}
	return dp[N].second;
}

//inline double solve(){
//	for(int k=1; k<=K; k++){
//		deque<int> dq; dq.pb(0);
//		for(int i=1; i<=N; i++){
//			while(dq.size() >= 2 && dp2[k-1][dq[0]]*i-dq[0] <= dp2[k-1][dq[1]]*i-dq[1]) dq.pop_front();
//			dp2[k][i] = (dp2[k-1][dq[0]]*i-dq[0])/i+1;
//			while(dq.size() >= 2 && inter(k,dq[dq.size()-2],i) <= inter(k,dq[dq.size()-2],dq.back())) dq.pop_back();
//			dq.pb(i);
//		}
//	}
//	return dp2[K][N];
//}

int main(){
	scanf("%d %d",&N,&K);
	double low = 0, high = 20, ans = 0;
	while(high-low >= 1e-15){
		double mid = (low+high)/2;
		int g = getGroups(mid);
		if(g <= K){
			ans = mid;
			high = mid-1e-15;
		}else low = mid+1e-15;
	}
	getGroups(ans);
	ld res = dp[N].first+ans*K;
	printf("%.8Lf\n",res);
}
/*
2 1
ans=1.5
 */

Compilation message

akvizna.cpp: In function 'int main()':
akvizna.cpp:134:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d %d",&N,&K);
  ~~~~~^~~~~~~~~~~~~~~

Subtask #1
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 25 ms 25336 KB Output is correct
2 Correct 25 ms 25336 KB Output is correct
3 Correct 25 ms 25336 KB Output is correct

Subtask #2
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 24 ms 25336 KB Output is correct
2 Correct 25 ms 25336 KB Output is correct
3 Correct 25 ms 25336 KB Output is correct

Subtask #3
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 29 ms 25464 KB Output is correct
2 Correct 25 ms 25336 KB Output is correct
3 Correct 25 ms 25336 KB Output is correct

Subtask #4
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 24 ms 25340 KB Output is correct
2 Correct 25 ms 25336 KB Output is correct
3 Correct 25 ms 25336 KB Output is correct

Subtask #5
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 84 ms 25564 KB Output is correct
2 Correct 91 ms 25544 KB Output is correct
3 Correct 85 ms 25464 KB Output is correct

Subtask #6
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 88 ms 25592 KB Output is correct
2 Correct 90 ms 25464 KB Output is correct
3 Correct 86 ms 25464 KB Output is correct

Subtask #7
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 86 ms 25508 KB Output is correct
2 Correct 86 ms 25464 KB Output is correct
3 Correct 82 ms 25464 KB Output is correct

Subtask #8
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 91 ms 25464 KB Output is correct
2 Correct 91 ms 25436 KB Output is correct
3 Correct 85 ms 25540 KB Output is correct

Subtask #9
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 85 ms 25464 KB Output is correct
2 Correct 90 ms 25464 KB Output is correct
3 Correct 83 ms 25464 KB Output is correct

Subtask #10
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 80 ms 25464 KB Output is correct
2 Correct 91 ms 25464 KB Output is correct
3 Correct 89 ms 25464 KB Output is correct

Subtask #11
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 88 ms 25464 KB Output is correct
2 Correct 91 ms 25468 KB Output is correct
3 Correct 89 ms 25504 KB Output is correct

Subtask #12
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 85 ms 25508 KB Output is correct
2 Correct 88 ms 25516 KB Output is correct
3 Correct 86 ms 25464 KB Output is correct

Subtask #13
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 89 ms 25464 KB Output is correct
2 Correct 87 ms 25592 KB Output is correct
3 Correct 87 ms 25556 KB Output is correct

Subtask #14
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1568 ms 28296 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #15
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1557 ms 28280 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #16
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1562 ms 28536 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #17
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1570 ms 28408 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #18
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1568 ms 28408 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #19
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1579 ms 28408 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #20
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1562 ms 28408 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #21
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1574 ms 28284 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #22
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1569 ms 28408 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #23
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1572 ms 28408 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #24
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1570 ms 28540 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #25
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1561 ms 28536 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #26
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1568 ms 28568 KB Time limit exceeded
2 Halted 0 ms 0 KB -