제출 #144027

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
144027		Kanon	Rectangles (IOI19_rect)	C++14	72 / 100	3163 ms	1048580 KiB

rect

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace __gnu_pbds;
using namespace std;

#define ordered_set tree<long long, null_type, greater<long long>, rb_tree_tag,tree_order_statistics_node_update>
#define range(i, m, n) for(int i = m; i < n; i++)
#define husk(i, m, n) for(int i = m; i > n; i--)

long long count_rectangles(vector<vector<int>> a) {
  int m = a.front().size();
  int n = a.size();
  auto pos = [&] (vector<int> cur) {
    int s = cur.size();
    vector<pair<int, int>> res;
    vector<int> st;
    range(i, 0, s) {
      while(st.size() && cur[st.back()] <= cur[i]) {
        if(st.back() < i - 1) res.emplace_back(st.back() + 1, i - 1);
        int b = st.back();
        st.pop_back();
        if(cur[b] == cur[i]) goto A;
      }
      if(st.size() && st.back() < i - 1) res.emplace_back(st.back() + 1, i - 1);
      A:;
      st.push_back(i);
    }
    return res;
  };
  vector<vector<set<pair<int, int>>>> hp, vs;
  hp.resize(n); for(auto &i : hp) i.resize(m);
  vs.resize(n); for(auto &i : vs) i.resize(m);
  range(i, 0, n) {
    vector<pair<int, int>> foo = pos(a[i]);
    for(auto u : foo) {
      int l = u.first, r = u.second;
      pair<int, int> p = make_pair(l, i);
      if(i && hp[i - 1][r].lower_bound(make_pair(l, -1))->first == l) p.second = hp[i - 1][r].lower_bound(make_pair(l, -1))->second;
      hp[i][r].insert(p);
    }
  }
  range(i, 0, m) {
    vector<int> ss(n);
    range(j, 0, n) ss[j] = a[j][i];
    vector<pair<int, int>> foo = pos(ss);
    for(auto u : foo) {
      int l = u.first, r = u.second;
      pair<int, int> p = make_pair(l, i);
      if(i && vs[r][i - 1].lower_bound(make_pair(l, -1))->first == l) p.second = vs[r][i - 1].lower_bound(make_pair(l, -1))->second;
      vs[r][i].insert(p);
    }
  }
  long long res = 0;
  auto cnt = [&](set<pair<int, int>> &x, set<pair<int, int>> &y) {
    vector<pair<int, int>> sy;
    for(auto i : y) {
      swap(i.first, i.second);
      sy.push_back(i);
    }
    sort(sy.begin(), sy.end());
    reverse(sy.begin(), sy.end());
    ordered_set cur;
    auto it = x.begin();
    int p = sy.size() - 1;
    while(it != x.end()) {
      while(~p && sy[p].first <= it->first) {
        cur.insert(sy[p].second);
        p--;
      }
      res += cur.order_of_key(it->second - 1);
      it++;
    }
  };
  range(i, 0, n) {
    range(j, 0, m) {
      cnt(hp[i][j], vs[i][j]);
    }
  }
  return res;
}

• Subtask 1: 8 / 8
• Subtask 2: 7 / 7
• Subtask 3: 12 / 12
• Subtask 4: 22 / 22
• Subtask 5: 10 / 10
• Subtask 6: 13 / 13
• Subtask 7: 0 / 28