이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <time.h>
#include <limits.h>
using namespace std;
typedef long long ll;
typedef double lf;
const int N_ = 100050;
int K, N;
ll sum_of_same_part;
ll S[N_], T[N_];
struct ele {
int w, x;
ele (int w = 0, int x = 0): w(w), x(x) { }
bool operator < (const ele &e) const { return x < e.x; }
} E[N_+N_]; int EN;
ll ans;
void solve1() {
int x = E[EN/2].x;
for(int i = 1; i <= EN; i++) ans += abs(x - E[i].x);
}
priority_queue<ll> pq1;
priority_queue<ll, vector<ll>, greater<ll> > pq2;
ll sum_pq1, sum_pq2;
int A[N_];
bool cmpA (const int &a, const int &b) {
return S[A[a]] + T[A[a]] < S[A[b]] + T[A[b]];
}
void pq_ins (ll v) {
if(!pq1.empty() && v > pq1.top()) pq2.push(v), sum_pq2 += v;
else pq1.push(v), sum_pq1 += v;
int md = (pq1.size() + pq2.size() + 1) / 2;
while(pq1.size() > md) {
sum_pq1 -= pq1.top();
sum_pq2 += pq1.top();
pq2.push(pq1.top());
pq1.pop();
}
while(pq1.size() < md) {
sum_pq2 -= pq2.top();
sum_pq1 += pq2.top();
pq1.push(pq2.top());
pq2.pop();
}
}
ll tb1[N_];
ll tb2[N_];
void solve2() {
ans = (ll)1e18;
if(EN == 0) { ans = 0; return; }
for(int i = 1; i <= N; i++) A[i] = i;
sort(A + 1, A + N + 1, cmpA);
for(int i = 1; i <= N; i++) {
// pq1 : max heap, pq2 : min heap
int x = A[i];
pq_ins(S[x]);
pq_ins(T[x]);
ll m = pq1.top();
tb1[i] = (m * pq1.size() - sum_pq1) + (sum_pq2 - m * pq2.size());
}
while(!pq1.empty()) pq1.pop(); sum_pq1 = 0;
while(!pq2.empty()) pq2.pop(); sum_pq2 = 0;
for(int i = N; i >= 1; i--) {
// pq1 : max heap, pq2 : min heap
int x = A[i];
pq_ins(S[x]);
pq_ins(T[x]);
ll m = pq1.top();
tb2[i] = (m * pq1.size() - sum_pq1) + (sum_pq2 - m * pq2.size());
}
for(int i = 1; i < N; i++) {
ans = min(ans, tb1[i] + tb2[i + 1]);
}
}
int main() {
int M; scanf("%d%d", &K, &M);
for(; M--; ) {
char p[3], q[3]; int s, t;
scanf("%s%d%s%d", p, &s, q, &t);
if(*p == *q) {
sum_of_same_part += abs(s - t);
}else {
++N;
if(s > t) swap(s, t);
S[N] = s; T[N] = t;
E[++EN] = ele(-N, s);
E[++EN] = ele(+N, t);
}
}
sort(E+1, E+EN+1);
E[EN+1].x = (int)2e9;
if(K == 1) solve1();
else solve2();
printf("%lld\n", ans + sum_of_same_part + N);
return 0;
}
컴파일 시 표준 에러 (stderr) 메시지
bridge.cpp: In function 'void pq_ins(ll)':
bridge.cpp:50:22: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
while(pq1.size() > md) {
^
bridge.cpp:56:22: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
while(pq1.size() < md) {
^
bridge.cpp: In function 'int main()':
bridge.cpp:107:33: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
int M; scanf("%d%d", &K, &M);
^
bridge.cpp:110:40: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
scanf("%s%d%s%d", p, &s, q, &t);
^
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