This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#define lsb(x) (x & (-x))
#define ll long long
#define ull unsigned long long
/*const int MOD = ;
inline int lgput(int a, int b) {
int ans = 1;
while(b > 0) {
if(b & 1) ans = (1LL * ans * a) % MOD;
b >>= 1;
a = (1LL * a * a) % MOD;
}
return ans;
}
inline void mod(int &x) {
if(x >= MOD)
x -= MOD;
}
inline void add(int &x, int y) {
x += y;
mod(x);
}
inline void sub(int &x, int y) {
x += MOD - y;
mod(x);
}
inline void mul(int &x, int y) {
x = (1LL * x * y) % MOD;
}
inline int inv(int x) {
return lgput(x, MOD - 2);
}*/
/*int fact[], invfact[];
inline void prec(int n) {
fact[0] = 1;
for(int i = 1; i <= n; i++) {
fact[i] = (1LL * fact[i - 1] * i) % MOD;
}
invfact[n] = lgput(fact[n], MOD - 2);
for(int i = n - 1; i >= 0; i--) {
invfact[i] = (1LL * invfact[i + 1] * (i + 1)) % MOD;
}
}
inline int comb(int n, int k) {
if(n < k) return 0;
return (1LL * fact[n] * (1LL * invfact[k] * invfact[n - k] % MOD)) % MOD;
}*/
using namespace std;
int main() {
#if 0
ifstream cin("A.in");
ofstream cout("A.out");
#endif
int i, j, n, k, md;
ios::sync_with_stdio(false);
cin.tie(0), cout.tie(0);
cin >> n >> k >> md;
vector < pair <int, int> > arr(n);
for(i = 0; i < n; i++) {
cin >> arr[i].first >> arr[i].second;
}
sort(arr.begin(), arr.end());
vector <int> mx(k + 1);
i = 0;
while(i < n && 2 * arr[i].first <= arr[n - 1].first) {
mx[arr[i].second]++;
i++;
}
vector <int> fr(k + 1);
for(i = 0; i < n; i++) {
fr[arr[i].second]++;
}
vector <bool> used(k + 1);
int ans = 0, p = n - 1;
for(i = n - 1; i >= 0; i--) {
if(used[arr[i].second]) continue;
while(p >= 0 && arr[i].first < 2 * arr[p].first) {
fr[arr[p].second]--;
p--;
}
int cur = 1;
for(j = 1; j <= k; j++) {
if(used[j] == 0) {
cur = (1LL * cur * (fr[j] + 1)) % md;
}
}
ans = (ans + cur) % md;
if(mx[arr[i].second] == fr[arr[i].second]) {
int num = 1;
cur = 1;
for(j = 1; j <= k; j++) {
if(j != arr[i].second)
cur = (1LL * cur * (fr[j] + 1)) % md;
if(j != arr[i].second && used[j] == 0)
num = (1LL * num * (fr[j] + 1)) % md;
}
ans = (ans + cur - num + md) % md;
}
used[arr[i].second] = 1;
}
cout << ans;
return 0;
}
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