Submission #143555

#TimeUsernameProblemLanguageResultExecution timeMemory
143555popovicirobertFish (IOI08_fish)C++14
4 / 100
3087 ms13788 KiB
#include <bits/stdc++.h> #define lsb(x) (x & (-x)) #define ll long long #define ull unsigned long long /*const int MOD = ; inline int lgput(int a, int b) { int ans = 1; while(b > 0) { if(b & 1) ans = (1LL * ans * a) % MOD; b >>= 1; a = (1LL * a * a) % MOD; } return ans; } inline void mod(int &x) { if(x >= MOD) x -= MOD; } inline void add(int &x, int y) { x += y; mod(x); } inline void sub(int &x, int y) { x += MOD - y; mod(x); } inline void mul(int &x, int y) { x = (1LL * x * y) % MOD; } inline int inv(int x) { return lgput(x, MOD - 2); }*/ /*int fact[], invfact[]; inline void prec(int n) { fact[0] = 1; for(int i = 1; i <= n; i++) { fact[i] = (1LL * fact[i - 1] * i) % MOD; } invfact[n] = lgput(fact[n], MOD - 2); for(int i = n - 1; i >= 0; i--) { invfact[i] = (1LL * invfact[i + 1] * (i + 1)) % MOD; } } inline int comb(int n, int k) { if(n < k) return 0; return (1LL * fact[n] * (1LL * invfact[k] * invfact[n - k] % MOD)) % MOD; }*/ using namespace std; int main() { #if 0 ifstream cin("A.in"); ofstream cout("A.out"); #endif int i, j, n, k, md; ios::sync_with_stdio(false); cin.tie(0), cout.tie(0); cin >> n >> k >> md; vector < pair <int, int> > arr(n); for(i = 0; i < n; i++) { cin >> arr[i].first >> arr[i].second; } sort(arr.begin(), arr.end()); vector <int> mx(k + 1); i = 0; while(i < n && 2 * arr[i].first <= arr[n - 1].first) { mx[arr[i].second]++; i++; } vector <int> fr(k + 1); for(i = 0; i < n; i++) { fr[arr[i].second]++; } vector <bool> used(k + 1); int ans = 0, p = n - 1; for(i = n - 1; i >= 0; i--) { if(used[arr[i].second]) continue; while(p >= 0 && arr[i].first < 2 * arr[p].first) { fr[arr[p].second]--; p--; } int cur = 1; for(j = 1; j <= k; j++) { if(used[j] == 0) { cur = (1LL * cur * (fr[j] + 1)) % md; } } ans = (ans + cur) % md; if(mx[arr[i].second] == fr[arr[i].second]) { int num = 1; cur = 1; for(j = 1; j <= k; j++) { if(j != arr[i].second) cur = (1LL * cur * (fr[j] + 1)) % md; if(j != arr[i].second && used[j] == 0) num = (1LL * num * (fr[j] + 1)) % md; } ans = (ans + cur - num + md) % md; } used[arr[i].second] = 1; } cout << ans; return 0; }
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