이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//#pragma GCC optimize("O3")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,tune=native")
//#pragma GCC optimize ("unroll-loops")
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ld = long double;
const int mod = 1e9 + 7;
const int N = 1e5 + 5;
const int K = 205;
struct line {
ll a;
ll b;
int pos;
};
struct CHT {
int last,top;
line ln[N];
inline bool Check(line& a,line& b,line& c) {
return (ld)(a.b-b.b)*(c.a-b.a)<(ld)(b.b-c.b)*(b.a-a.a);
}
inline bool Check2(line& a,line& b,int x) {
return (ll)x*(b.a-a.a)<a.b-b.b;
}
void insert(line u) {
if(top&&ln[top-1].a==u.a&&ln[top-1].b>=u.b) return;
while(top>=2&&!Check(ln[top-2],ln[top-1],u)) top--;
ln[top++]=u;
}
line query(int x) {
last=min(last,top-1);
while(last+1<top&&!Check2(ln[last],ln[last+1],x))last++;
return ln[last];
}
void clear() {
last=0; top=0;
}
}cht;
ll pref[N];
ll dp[K][N];
int way[K][N];
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
cout.tie(nullptr);
int n, k;
cin >> n >> k;
for (int i = 1; i <= n; i++) {
cin >> pref[i];
pref[i] += pref[i - 1];
}
for (int i = 1; i <= k; i++) {
cht.clear();
cht.insert({ pref[i], dp[i - 1][i] - pref[i] * pref[i], i });
for (int j = i + 1; j <= n; j++) {
auto p = cht.query(pref[j]);
dp[i][j] = p.a * pref[j] + p.b;
way[i][j] = p.pos;
cht.insert({ pref[j], dp[i - 1][j] - pref[j] * pref[j], j });
}
}
cout << dp[k][n] << '\n';
int kek = n;
vector<int> ans;
for (int i = k; i > 0; i--) {
ans.push_back(way[i][kek]);
kek = way[i][kek];
}
reverse(ans.begin(), ans.end());
for (int i : ans) {
cout << i << ' ';
}
return 0;
}
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