제출 #140145

#	제출 시각UTC-0	아이디	문제	언어	결과	실행 시간	메모리
140145	2019-08-02 07:43:29	rdd6584	Unifying Values (KRIII5_UV)	C++14	7 / 7	361 ms	764 KiB

UV

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#include <cstdio>
#include <algorithm>
#include <memory.h>
#include <iostream>
using namespace std;
typedef long long ll;
const int MOD = 1000000007;
ll vec[10000];
int dp[10001];
int main() {
  ios::sync_with_stdio(false);
  cin.tie(0); cout.tie(0);
  int n;
  cin >> n;
  for (int i = 0; i < n; i++) {
    cin >> vec[i];
    if (i) vec[i] += vec[i - 1];
  }
  ll ans = 0;
  for (int i = 0; i < n - 1; i++) {
    if (!vec[i] || vec[n - 1] % vec[i]) continue;
    ll t = vec[n - 1] / vec[i];
    if (vec[i] > 0 && vec[n - 1] < 0 || vec[i] < 0 && vec[n - 1] > 0) continue;
    if (t < 2 || t > 10000) continue;
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX

컴파일 시 표준 에러 (stderr) 메시지

UV.cpp: In function 'int main()':
UV.cpp:29:18: warning: suggest parentheses around '&&' within '||' [-Wparentheses]
   if (vec[i] > 0 && vec[n - 1] < 0 || vec[i] < 0 && vec[n - 1] > 0) continue;
       ~~~~~~~~~~~^~~~~~~~~~~~~~~~~

• Subtask 1: 2 / 2
• Subtask 2: 5 / 5