제출 #138396

#제출 시각아이디문제언어결과실행 시간메모리
138396Runtime_error_Aliens (IOI16_aliens)C++14
25 / 100
2043 ms56056 KiB
#include "aliens.h" #include <bits/stdc++.h> #define ll long long using namespace std; const ll inf = 1e5+9,K = 509,MX = 1e18+9; ll sqr(ll x){ return x*x; } //ll dp[K][inf]; pair<ll,ll> a[inf]; vector<pair<ll,ll> > all; bool cmp(pair<ll,ll>x,pair<ll,ll>y ){ if(x.first == y.first) return x.second > y.second; return x.first<y.first; } // this code to get maximum // to get minimum use -m , -p , -query bool Q ; struct Line { mutable ll m, p, k; bool operator<(const Line& o) const { return Q ? k < o.k : m < o.m; } }; struct LineContainer : multiset<Line> { // (for doubles, use inf = 1/.0, div(a,b) = a/b) const ll inf = LLONG_MAX; ll div(ll a, ll b) { // floored division return a / b - ((a ^ b) < 0 && a % b); } bool isect(iterator x, iterator y) { if (y == end()) { x->k = inf; return false; } if (x->m == y->m) x->k = x->p > y->p ? inf : -inf; else x->k = div(y->p - x->p, x->m - y->m); return x->k >= y->k; } void add(ll m, ll p) { auto z = insert({m, p, 0}), y = z++, x = y; while (isect(y, z)) z = erase(z); if (x != begin() && isect(--x, y)) isect(x, y = erase(y)); while ((y = x) != begin() && (--x)->k >= y->k) isect(x, erase(y)); } ll query(ll x) { if(empty()) return -MX; assert(!empty()); Q = 1; auto l = *lower_bound({0,0,x}); Q = 0; return l.m * x + l.p; } }lc; ll take_photos(int n, int m, int k, vector<int> r, vector<int> c) { for(ll i=0;i<n;i++) r[i] ++,c[i]++, all.push_back( make_pair(min(r[i],c[i]),max(r[i],c[i]) ) ); sort(all.begin(),all.end(),cmp); n = 1; a[1] = all[0]; for(auto o:all){ if(o.second <= a[n].second) continue; a[++n] = make_pair(o.first,o.second); } k = min(k,n); ll dp[k+2][n+2] = {0}; memset(dp,61,sizeof(dp)); dp[0][0] = 0; for(ll j=1;j<=k;j++){ for(ll i=1;i<=n;i++){ ll m = -2ll * a[i].first , p = sqr(a[i].first) + dp[j-1][i-1] - sqr(max(0ll,a[i-1].second - a[i].first+1) ) - 2ll*a[i].first; lc.add(-m,-p); ll add = sqr(a[i].second) + 2ll*a[i].second + 1 , x = a[i].second; dp[j][i] = add - lc.query(x); /*for(ll z = 1;z<=i;z++) dp[j][i] = min( dp[j][i] , dp[j-1][z-1] + sqr(a[i].second - a[z].first+1) - sqr(max(0ll,a[z-1].second - a[z].first+1) ) );*/ } } return dp[k][n]; }
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