#include<cstdio>
#include<algorithm>
#include<deque>
#include<stdlib.h>
#include<time.h>
#include<cstring>
#define MOD (ll)(1e9)
using namespace std;
typedef long long ll;
typedef pair<ll,ll> pp;
ll d[2][1010],s[100010],N,K;
short r[201][1001];
void f(int x,int y){
if(x==1)return;
f(x-1,r[x][y]);
printf("%d ",(int)r[x][y]);
}
/*void f2(int x,int y){
if(x==1)return;
f(x-1,r2[x][y]);
printf("%d ",(int)r2[x][y]);
}*/
struct convex{
deque<ll> a,b,c;
void init(){a.clear();b.clear();c.clear();}
bool check(ll z0,ll z1,ll z2,ll z3){
ll uz0=z0/MOD,uz1=z1/MOD,uz2=z2/MOD,uz3=z3/MOD;
z0%=MOD,z1%=MOD,z2%=MOD,z3%=MOD;
ll p=0,q=0,r=0,p2=0,q2=0,r2=0;
r=z0*z1,r2=z2*z3;
q+=r/MOD,q2+=r2/MOD;
r%=MOD,r2%=MOD;
q+=z0*uz1+uz0*z1,q2+=z2*uz3+z3*uz2;
p+=q/MOD,p2+=q2/MOD;
q%=MOD,q2%=MOD;
p+=uz0*uz1,p2+=uz2*uz3;
if(p!=p2)return p>p2;
if(q!=q2)return q>q2;
return r>r2;
}
void push(ll n,ll m,ll v){
while(a.size()>1&&check(b.back()-b[b.size()-2],a.back()-n,m-b.back(),a[a.size()-2]-a.back())){
a.pop_back();
b.pop_back();
c.pop_back();
}
a.push_back(n);
b.push_back(m);
c.push_back(v);
}
pp query(ll x){
while(!a.empty()&&(a[0]-a[1])*x<(b[1]-b[0])){
a.pop_front();
b.pop_front();
c.pop_front();
}
return pp(a[0]*x+b[0],c[0]);
}
};
int main(){
srand(time(NULL));
scanf("%lld%lld",&N,&K);
//for(int comet=0;comet<100000;comet++){
if(K==0)K++;
for(int i=1;i<=N;i++){
scanf("%lld",&s[i]);
//s[i]=rand();
s[i]+=s[i-1];
}
convex* pre=new convex;
convex* cur=new convex;
pp ret;
for(int i=1;i<=N;i++){
d[1][i]=s[i]*(s[N]-s[i]);
pre->push(s[i],d[1][i]-s[i]*s[N],i);
}
for(int g=2;g<=K+1;g++){
for(int i=g;i<=N;i++){
ret=pre->query(s[i]);
d[g&1][i]=ret.first+(s[N]-s[i])*s[i];
r[g][i]=ret.second;
cur->push(s[i],d[g&1][i]-s[i]*s[N],i);
}
pre->init();
swap(cur,pre);
}
/*for(int i=1;i<=N;i++)d2[1][i]=s[i]*(s[N]-s[i]);
for(int g=2;g<=K+1;g++){
for(int i=g;i<=N;i++){
for(int j=1;j<i;j++){
if(d2[g%2][i]<d2[(g+1)%2][j]+(s[i]-s[j])*(s[N]-s[i])){
d2[g%2][i]=d2[(g+1)%2][j]+(s[i]-s[j])*(s[N]-s[i]);
r2[g][i]=j;
}
}
}
}*/
/*if(d[(K+1)&1][N]!=d2[(K+1)%2][N]){
printf("%lld %lld\n",N,K);
for(int i=1;i<=N;i++)printf("%lld ",s[i]);
printf("\nans= %lld, %lld\n",d[(K+1)&1][N],d2[(K+1)%2][N]);
f(K+1,N);
f2(K+1,N);
break;
}
*/
printf("%lld \n",d[(K+1)&1][N]);
f(K+1,N);
//f2(K+1,N);
delete cur,pre;
}
