| # | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
|---|---|---|---|---|---|---|---|
| 1356860 | yogesh_sane | Data Transfer (IOI19_transfer) | C++20 | 43 ms | 1724 KiB |
#include "transfer.h"
#include <vector>
#include <numeric>
#include <cmath>
using namespace std;
/**
* Calculates how many bits are needed to represent the indices of the source.
* N = 63 needs 6 bits (2^6 = 64)
* N = 255 needs 8 bits (2^8 = 256)
*/
int get_checksum_size(int n) {
return (n <= 63) ? 6 : 8;
}
vector<int> get_attachment(vector<int> source) {
int n = source.size();
int k = get_checksum_size(n);
vector<int> attachment;
// 1. Calculate Global Parity (Is the total number of 1s even or odd?)
int total_sum = accumulate(source.begin(), source.end(), 0);
attachment.push_back(total_sum % 2);
// 2. Calculate XOR Checksum (The "address" of the 1s)
int xor_sum = 0;
for (int i = 0; i < n; i++) {
if (source[i] == 1) {
xor_sum ^= (i + 1); // Use 1-based indexing so 0 doesn't disappear
}
}
// 3. Convert XOR sum to individual bits (Binary representation)
// We iterate from most significant bit to least significant
for (int bit = k - 1; bit >= 0; bit--) {
int bit_value = (xor_sum >> bit) & 1;
attachment.push_back(bit_value);
}
return attachment;
}
vector<int> retrieve(vector<int> data) {
// Determine N and K from the total size received
// The attachment was 1 (parity) + K (checksum) bits
int k = (data.size() <= 70) ? 6 : 8;
int n = data.size() - k - 1;
// 1. Extract the sent data and the checksum parts
vector<int> message;
for (int i = 0; i < n; i++) {
message.push_back(data[i]);
}
int sent_parity = data[n];
int sent_xor_sum = 0;
for (int i = 0; i < k; i++) {
int bit_value = data[n + 1 + i];
// Reconstruct the integer from the bits
if (bit_value == 1) {
sent_xor_sum |= (1 << (k - 1 - i));
}
}
// 2. Calculate what the parity and XOR sum SHOULD be based on received message
int actual_parity = accumulate(message.begin(), message.end(), 0) % 2;
int actual_xor_sum = 0;
for (int i = 0; i < n; i++) {
if (message[i] == 1) {
actual_xor_sum ^= (i + 1);
}
}
// 3. Error Detection Logic
bool parity_matches = (actual_parity == sent_parity);
bool xor_matches = (actual_xor_sum == sent_xor_sum);
// If parity matches, either there's no error or the error is in the attachment bits.
// If XOR matches, the message is clean.
if (parity_matches || xor_matches) {
return message;
}
// 4. Error Correction
// If both parity and XOR differ, a bit in the message flipped.
// The XOR of the 'sent' and 'actual' sums gives the exact position of the flip.
int error_index = (actual_xor_sum ^ sent_xor_sum) - 1;
// Safety check: only flip if the index is within the message range
if (error_index >= 0 && error_index < n) {
message[error_index] = 1 - message[error_index]; // Flip 0 to 1 or 1 to 0
}
return message;
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