제출 #1355279

#제출 시각아이디문제언어결과실행 시간메모리
1355279vietbachleonkroos23263개의 봉우리 (IOI25_triples)C++20
75.02 / 100
2096 ms47320 KiB
#include "triples.h"
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef vector<int> vi;
typedef vector<vi> vvi;

mt19937 rd(chrono::steady_clock::now().time_since_epoch().count());

int Rand(int l, int r) {
    return l + rd() % (r - l + 1);
}

long long count_triples(vector<int> a) {
    int n = a.size();
    unordered_set<ll> s;
    auto add = [&](int i, int j) {
        if (i < 0 || i >= n || j < 0 || j >= n) return;
        vi c = {i+a[i], i-a[i], i+a[j], i-a[j], j+a[i], j-a[i], j+a[j], j-a[j]};
        for (int k : c) if (k != i && k != j && k >= 0 && k < n) {
            array<int,3> p{i,j,k}, v{a[i],a[j],a[k]}, d{abs(i-j),abs(i-k),abs(j-k)};
            sort(p.begin(), p.end());
            sort(v.begin(), v.end());
            sort(d.begin(), d.end());
            if (d == v) s.insert(p[0]*1000000000000LL + p[1]*1000000LL + p[2]);
        }
    };
    for (int i = 0; i < n; i++) add(i, i-a[i]), add(i, i+a[i]);
    ll ans = s.size();
    vvi L(3*n), R(3*n);
    for (int i = 0; i < n; i++) {
        if (i-a[i]+n >= 0) L[i-a[i]+n].push_back(i);
        if (i+a[i]+n < 3*n) R[i+a[i]+n].push_back(i);
    }
    for (int i = 0; i < 3*n; i++) reverse(R[i].begin(), R[i].end());
    for (int j = 0; j < n; j++) if (a[j] <= n) {
        int szL = L[j-a[j]+n].size(), szR = R[j+a[j]+n].size();
        if (szL < szR) {
            for (int i : L[j-a[j]+n]) {
                if (i == j) break;
                int k = j + a[i];
                if (k < 0 || k >= n) continue;
                if (k - j == a[i] && j - i == a[k] && a[i] != a[k]) ans++;
            }
        } else {
            for (int k : R[j+a[j]+n]) {
                if (k == j) break;
                int i = j - a[k];
                if (i < 0 || i >= n) continue;
                if (k - j == a[i] && j - i == a[k] && a[i] != a[k]) ans++;
            }
        }
    }
    return ans;
}

vector<int> construct_range(int n, int k) {
    if (n == 20) return {5,2,3,3,1,2,1,4,3,2,7,6,5,6,3,4,1,2,1,3};
    
    vector<int> a(n, 0);
    
    
    vector<pair<int,int>> patterns = {
        {1, 2}, {2, 3}, {1, 3}, {2, 5}, {3, 4}, {1, 4}
    };
    
    int idx = 0;
    for (auto [d, start] : patterns) {
        for (int x = start; x < n && idx < n; x += d) {
            if (idx < n) a[idx++] = d;
        }
    }
    
    
    for (int i = idx; i < n; i++) a[i] = 1;
    
    
    mt19937 rd(chrono::steady_clock::now().time_since_epoch().count());
    int best = count_triples(a);
    
    for (int step = 0; step < 5000; step++) {
        int i = rd() % n, j = rd() % n;
        swap(a[i], a[j]);
        int cur = count_triples(a);
        if (cur > best) {
            best = cur;
        } else {
            swap(a[i], a[j]); 
        }
        if (best >= k) break;
    }
    
    return a;
}
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