제출 #135268

#제출 시각아이디문제언어결과실행 시간메모리
135268pedro_sponchiado수열 (APIO14_sequence)C++17
49 / 100
173 ms131076 KiB
#include<bits/stdc++.h> using namespace std; const long long int INF=12345678912345678; const int maxn=100010; const int maxk=201; int n, d; int a[maxn]; long long int parc[maxn], parc_2[maxn]; long long int s_2[maxn]; long long int S_2(int i, int j){ return s_2[j]-s_2[i-1]-parc[i-1]*(parc[j]-parc[i-1]); } long long int dp[maxn][maxk]; int opt[maxn][maxk]; void resolve(int k, int ini, int fin, int opt_min, int opt_max){ int m=(ini+fin)/2; dp[m][k]=INF; for(int l=opt_min; l<=opt_max && l<m; l++){ if(dp[m][k]>dp[l][k-1]+S_2(l+1, m)){ dp[m][k]=dp[l][k-1]+S_2(l+1, m); opt[m][k]=l; } } if(ini!=fin){ resolve(k, ini, m, opt_min, opt[m][k]); resolve(k, m+1, fin, opt[m][k], opt_max); } return; } int main(){ scanf("%d %d", &n, &d); for(int i=1; i<=n; i++){ scanf("%d", &a[i]); parc[i]=parc[i-1]+a[i]; parc_2[i]=parc_2[i-1]+a[i]*a[i]; s_2[i]=(parc[i]*parc[i]-parc_2[i])/2; } for(int i=1; i<=n; i++) dp[i][0]=s_2[i]; for(int k=1; k<=d; k++){ resolve(k, 1, n, 1, n); } printf("%lld\n", s_2[n]-dp[n][d]); /* for(int i=1; i<=n; i++){ for(int k=1;k<=d; k++){ printf("%d ", dp[i][k]); } printf("\n"); } */ int at=n; vector<int> aux; for(int i=d; i>=1; i--){ aux.push_back(opt[at][i]); at=opt[at][i]; } for(int i=d-1; i>=0; i--) printf("%d ", aux[i]); return 0; }

컴파일 시 표준 에러 (stderr) 메시지

sequence.cpp: In function 'int main()':
sequence.cpp:36:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d %d", &n, &d);
  ~~~~~^~~~~~~~~~~~~~~~~
sequence.cpp:38:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%d", &a[i]);
   ~~~~~^~~~~~~~~~~~~
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