Submission #1351135

#TimeUsernameProblemLanguageResultExecution timeMemory
1351135FIFI_cppExponents (BOI25_exp)C++20
37 / 100
78 ms23092 KiB
#include <bits/stdc++.h>
#include <iostream>
#include <vector>
#include <algorithm>
#include <numeric>
#include <cstdlib>
#include <cmath>
#include <queue>
#include <stack>
#include <deque>
#include <fstream>
#include <iterator>
#include <set>
#include <map>
#include <unordered_map>
#include <iomanip>
#include <cctype>
#include <string>
#include <cassert>
#include <set>
#include <bitset>
#include <unordered_set>
#include <numeric>

#define all(a) a.begin(), a.end()
#define fast ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
#define pb push_back
#define ppi pair<int,pair<int,int>>
#define int int64_t

using namespace std;
//    /\_/\
//   (= ._.)
//   / >  \>
// encouraging cat
const int INF = 10000000000000000;
//const int mod = 1000000007;
const int mod = 998244353;
const int MAXN = 2002;
//ifstream fin('xor.in');
//ofstream fout('xor.out');
int dp[MAXN][MAXN];
signed main()
{
    int n,q;
    cin >> n >> q;
    vector<int> a(n);
    for (int i = 0;i < n;i++)
    {
        cin >> a[i];
    }
    for (int i = 0;i < n;i++)
    {
        dp[i][i] = a[i];
    }
    for (int sz = 2;sz <= n;sz++)
    {
        for (int i = 0;i < n;i++)
        {
            int r = i + sz - 1;
            if (r >= n)
            {
                break;
            }
            int lo = i, hi = r - 1, mid = (lo + hi + 1) / 2;
            while (lo < hi)
            {
                mid = (lo + hi + 1) / 2;
                if (dp[i][mid] <= dp[mid + 1][r])
                {
                    lo = mid;
                }
                else
                {
                    hi = mid - 1;
                }
            }
            dp[i][r] = max(dp[i][lo], dp[lo + 1][r]) + 1;
            if (lo < r)
            {
                dp[i][r] = min(dp[i][r], max(dp[i][lo + 1], dp[lo + 1][r]) + 1);
            }
        }
    }
    while (q--)
    {
        int l,r;
        cin >> l >> r;
        l--,r--;
        cout << dp[l][r] << '\n';
    }
    return 0;
}
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