| # | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
|---|---|---|---|---|---|---|---|
| 1351012 | dex111222333444555 | Bootfall (IZhO17_bootfall) | C++20 | 622 ms | 3104 KiB |
#include <bits/stdc++.h>
#define all(v) begin(v), end(v)
#define dbg(x) "[" #x " = " << x << "]"
#define ii pair<int, long long>
#define fi first
#define se second
#define siz(v) (int)(v).size()
#define lli pair<long long, int>
#define BIT(x, i) (((x) >> (i)) & 1)
using namespace std;
const int infINT = 1e9 + 1323;
const long long mod = 1e18 + 7, inf = 1e18 + 123123;
template<class X, class Y> bool minimize(X &x, const Y &y){return x > y ? x = y, 1: 0;}
template<class X, class Y> bool maximize(X &x, const Y &y){return x < y ? x = y, 1: 0;}
void add(long long &a, const long long &b){
a += b;
if (a >= mod) a -= mod;
}
void sub(long long &a, const long long &b){
a -= b;
if (a < 0) a += mod;
}
long long mul(const long long &a, const long long &b){
return 1LL * a * 1LL * b % mod;
}
const int MAXN = 505;
int numVal, val[MAXN], sum;
long long f[MAXN * MAXN];
bool res[MAXN * MAXN];
void input(){
cin >> numVal;
for(int i = 1; i <= numVal; i++) cin >> val[i], sum += val[i];
}
void solve(){
f[0] = 1;
for(int i = 1; i <= numVal; i++){
for(int j = sum - val[i]; j >= 0; j--){
add(f[j + val[i]], f[j]);
}
}
for(int i = 0; i <= sum; i++) res[i] = ((sum % 2 == 0) && (f[sum / 2]));
for(int i = 1; i <= numVal; i++){
for(int j = 0; j <= sum - val[i]; j++){
sub(f[j + val[i]], f[j]);
}
for(int j = 1; j <= sum; j++){
int nsum = sum + j - val[i];
res[j] &= ((nsum % 2 == 0) && ((f[nsum / 2]) || ((nsum / 2 >= j) && f[nsum / 2 - j])));
}
for(int j = sum - val[i]; j >= 0; j--){
add(f[j + val[i]], f[j]);
}
}
int cnt = 0;
for(int j = 1; j <= sum; j++) cnt += res[j];
cout << cnt << '\n';
for(int j = 1; j <= sum; j++) if (res[j]) cout << j << ' '; cout << '\n';
}
bool M1;
bool M2;
signed main(){
ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define task "BOOTFALL"
if (fopen(task".in", "r")){
freopen(task".in", "r", stdin);
freopen(task".out", "w", stdout);
}
input();
solve();
cerr << (&M2 - &M1) / 1048576 << " mb\n";
cerr << (1.0 * clock()) / CLOCKS_PER_SEC << ".s\n";
}
컴파일 시 표준 에러 (stderr) 메시지
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