제출 #1350663

#제출 시각아이디문제언어결과실행 시간메모리
1350663vjudge1Bitaro the Brave (JOI19_ho_t1)C++20
100 / 100
214 ms153428 KiB
/// Author: Raiz
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/hash_policy.hpp>

#pragma GCC target("sse,sse2,sse3,ssse3,popcnt,abm,mmx,tune=native")
#pragma GCC optimize("Ofast")
#pragma GCC optimize("no-stack-protector")
#pragma GCC optimize("unroll-loops")
#pragma GCC optimize("fast-math")

#define int long long // Don't forget!!
#define __Lek_Raiz                \
    ios_base::sync_with_stdio(0); \
    cin.tie(nullptr);             \
    cout.tie(nullptr)
#define all(v) v.begin(), v.end()
#define rall(v) v.rbegin(), v.rend()
#define ll long long
#define str string
#define pb push_back
#define pf push_front
#define ep emplace_back
#define pii pair<int, int>
#define FOR0(i, n) for (int i = 0; i < n; ++i)
#define FOR1(i, n) for (int i = 1; i <= n; ++i)
/// #define size(x) (int)x.size()
#define rs(x) resize(x)
#define vi vector<int>
#define input1(v)                \
    for (int i = 1; i <= n; ++i) \
    cin >> v[i]

using namespace std;
using namespace __gnu_pbds;

template <typename T>
using __indexed_multiset = tree<T, null_type, less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>;

template <typename T>
using __indexed_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;

mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
/// priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> pq;

const int sz = 1e4 + 31; // hmm... RunTime error?
const int LOG = 63;
const int sz2 = 1e3 + 31;
const int MOD = 1e9 + 7;
const int INF = 1e18;
// cd Documents && cd Cpp && g++ main.cpp -o main && ./main

// variables:
int n, m;

void solve()
{
    cin >> n >> m;

    vector<vector<char>> a(n + 1, vector<char>(m + 1));
    for (int i = 1; i <= n; ++i)
    {
        for (int j = 1; j <= m; ++j)
        {
            cin >> a[i][j];
        }
    }

    vector<vi> prefO(n + 31, vi(m + 31)), prefI(m + 31, vi(n + 31));

    for (int i = 1; i <= n; ++i)
    {
        for (int j = m; j >= 1; --j)
        {
            prefO[i][j] = prefO[i][j + 1] + (a[i][j] == 'O');
        }
    }

    for (int j = 1; j <= m; ++j)
    {
        for (int i = n; i >= 1; --i)
        {
            prefI[j][i] = prefI[j][i + 1] + (a[i][j] == 'I');
        }
    }

    int cnt = 0;
    for (int i = 1; i <= n; ++i)
    {
        for (int j = 1; j <= m; ++j)
        {
            if (a[i][j] == 'J')
            {
                cnt += (prefO[i][j + 1] * prefI[j][i + 1]);
            }
        }
    }

    cout << cnt << "\n";
}

signed main()
{
    __Lek_Raiz;
    // freopen("bcount.in", "r", stdin);
    // freopen("bcount.out" , "w", stdout);
    // sieve();

    int t = 1;
    /// cin >> t;

    while (t-- > 0)
    {
        solve();
    }
}
/*
.....               ....................   .......            ........ .....
.+@@*               .-@@@@@@@@@@@@@@@@@+    =%@%-.        ..:*%@@@=... =%@%:.
.+@@*               .-@@@%%%%%%%%%%%%%%+    =%@%-.       .+%@@@*-..    =%@%:
.+@@*               .-@@#:...............   =%@%-.   ..=#%@@#=:...     =%@%:
.+@@*               .-@@#:.                 =%@%-. .-*%@@%*-....       =%@%:
.+@@*               .-@@%#*************=    =%@@#**%@@@#=...           =%@%:
.+@@*               .-@@@@@@@@@@@@@@@@@*    =%@@@@@@@@%+:.             =%@%:
.+@@*               .-@@#:..............    =%@%-  .+%@@@%-..          =%@%:
.+@@*               .-@@#:.                 =%@%-. ...:*@@@%*:..       =%@%:
.+@@#::::::::::::::..=@@#-::::::::::::::    =%@%-...   ..-#@@@#=.      =%@%:
.+@@@@@@@@@@@@@@@@%-.=@@@@@@@@@@@@@@@@@*    =%@%-...      .:=%@@%*-.   =%@%:
.-****************+:.:*****************-.   :+*+:.           .-+***=.. -+*+.

*/
//
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